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FromTheMoon [43]
3 years ago
12

How long can a flashlight run for if it draws 0.11 amps and its battery contains 10 coulombs of change?

Physics
1 answer:
Alex17521 [72]3 years ago
8 0

Answer:

Battery will run for t = 90 s

Explanation:

As we know that rate of flow of charge is known as electric current

So we will have

i = \frac{Q}{t}

i = 0.11 A

Q = 10 C

now we have

t = \frac{Q}{i}

t = \frac{10}{0.11}

t = 90 s

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Which of the following statements are true?
ale4655 [162]

Answer:

A) True. Voltmeters measure voltages

C) True. They are placed in parallel

E) True ammeters are used to measure current

Explanation:

The devices for voltage measurement are the voltmeter and ammeter

Voltmeters have very high intense resistance and are placed in parallel

The ammeters have very small resist and are placed in series

Based on this establishment, let's analyze the statements

A) True. Voltmeters measure voltages

B) False has high intense resistance

C) True. They are placed in parallel

D) False ammeters are placed in series

E) True ammeters are used to measure current

F) False ammeters have a low internal resistance

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3 years ago
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Irina-Kira [14]
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8 0
3 years ago
A ball is dropped from a height of 23.5 meters. Assuming no air resistance, how many seconds will it take the ball to hit the
Alex Ar [27]

Answer:

About 2.19 seconds

Explanation:

d=v_ot+\dfrac{1}{2}at^2

Since the ball is dropped from rest, there is no initial velocity, and you can write the following equation:

23.5=\dfrac{1}{2}(9.8)t^2 \\\\t^2\approx 4.79 \\\\t\approx 2.19s

Hope this helps!

8 0
3 years ago
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define heat, sound, light and potential energy. please can I get a short definition for each energy and I need the answer now pl
inysia [295]
Heat is an energy that is produced from something like the sun. Sound energy is when an object works to make sound. Light is when something gives off light by working. And potential energy is when an object is completely still but can be moved by another force
4 0
3 years ago
A 7450 kg rocket blasts off vertically from the launch pad with a constant upward acceleration of 2.35 m/s2 and feels no appreci
bagirrra123 [75]

Answer:

a) 520m

b) 10.30 s

c) 100,95 m/s

Explanation:

a) According the given information, the rocket suddenly stops when it reach the height of 520m, because the engines fail, and then it begins the free fall.

This means the maximum height this rocket reached before falling  was 520 m.

b) As we are dealing with constant acceleration (due gravity) g=9.8 \frac{m}{s^{2}} we can use the following formula:

y=y_{o}+V_{o} t-\frac{gt^{2}}{2}   (1)

Where:

y_{o}=520 m  is the initial height of the rocket (at the exact moment in which it stops due engines fail)

y=0  is the final height of the rocket (when it finally hits the launch pad)

V_{o}=0 is the initial velocity of the rocket (at the exact moment in which it stops the velocity is zero and then it begins to fall)

g=9.8m/s^{2}  is the acceleration due gravity

t is the time it takes to the rocket to hit the launch pad

Clearing t:

0=520 m+0-\frac{9.8m/s^{2} t^{2}}{2}   (2)

t^{2}=\frac{-520 m}{-4.9 m/s^{2}}   (3)

t=\sqrt{106.12 s^{2}   (4)

t=10.30 s   (5)  This is the time

c) Now we need to find the final velocity V_{f} for this rocket, and the following equation will be perfect to find it:

V_{f}=V_{o}-gt  (6)

V_{f}=0-(9.8 m/s^{2})(10.30 s)  (7)

V_{f}=-100.95 m/s  (8) This is the final velocity of the rocket. Note the negative sign indicates its direction is downwards (to the launch pad)

7 0
3 years ago
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