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In-s [12.5K]
3 years ago
8

A car jack with a mechanical advantage of 6 needs to produce an output force of 600 N to raise a car. What input force is requir

ed?
Physics
2 answers:
Mkey [24]3 years ago
6 0

B.) 100 N is the CORRECT answer


Please mark as brainliest! :)

Free_Kalibri [48]3 years ago
3 0

MA = Mechanical advantage of car jack = 6

F_{o} = Output force required to raise the car = 600 N

F_{i} = Input force required to raise the car = ?

Mechanical advantage is given as

MA = F_{o} /F_{i}

inserting the values

6 = 600/F_{i}

F_{i} = 600/6

F_{i} = 100 N

Hence the input force required comes out to be 100 N

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A hot air balloon has a volume of 65,00 cubic feet of hot air. The balloon is at sea level on a standard day. If the temperature
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The velocity v(t) in the table below is increasing for 0_t_12.
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0.5-lbm of a saturated vapor is converted to asaturated liquid by being cooled in a weighted piston-cylinder device maintained a
klio [65]

Answer:

The boiling point temperature of this substance when its pressure is 60 psia is  480.275 R

Explanation:

Given the data in the question;

Using the Clapeyron equation

(\frac{dP}{dT} )_{sat } = \frac{h_{fg}}{Tv_{fg}}

(\frac{dP}{dT} )_{sat } = \frac{\frac{H_{fg}}{m} }{T\frac{V_{fg}}{m} }

where h_{fg is the change in enthalpy of saturated vapor to saturated liquid ( 250 Btu

T is the temperature ( 15 + 460 )R

m is the mass of water ( 0.5 Ibm )

V_{fg is specific volume ( 1.5 ft³ )

we substitute

(\frac{dP}{dT} )_{sat } =( \frac{250Btu\frac{778Ibf-ft}{Btu} }{0.5}) / ( (15+460)\frac{1.5}{0.5})  

(\frac{dP}{dT} )_{sat } = 272.98 Ibf-ft²/R

Now,

(\frac{dP}{dT} )_{sat } = (\frac{P_2 - P_1}{T_2 - T_1})_{sat

where P₁ is the initial pressure ( 50 psia )

P₂ is the final pressure ( 60 psia )

T₁ is the initial temperature ( 15 + 460 )R

T₂ is the final temperature = ?

we substitute;

T_2 = ( 15 + 460 ) + \frac{(60-50)psia(\frac{144in^2}{ft^2}) }{272.98}

T_2 = 475 + 5.2751\\

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Therefore, boiling point temperature of this substance when its pressure is 60 psia is  480.275 R

3 0
2 years ago
Relative formula mass of CuCO3
Elodia [21]

AnMolar mass of CuCO3 = 123.5549 g/mol

This compound is also known as Copper(II) Carbonate.

Convert grams CuCO3 to moles  or  moles CuCO3 to grams

Molecular weight calculation:

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Percent composition by element

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Oxygen O 15.9994 3 38.848%

Explanation:

5 0
2 years ago
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