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Anastasy [175]
3 years ago
12

If a maximum of 5.60g of a gas at 2.50 atm of pressure dissolves in 3.5-L of water, what will the solubility be if the pressure

Chemistry
1 answer:
KonstantinChe [14]3 years ago
6 0
According to Henry's law C = k P
where C = concentration of gas (g/L)
k : Henry's constant
P : pressure of gas above the solution
concentration of gas = 5.6 g / 3.5 L = 1.6 g/L
From Henry's law:
C₁ / C₂ = P₁ / P₂
C₂ = C₁P₂ / P₁ = (1.6 * 5 atm) / 2.5 atm = 3.2 g/L
so the 3.5 L will contain 11.2 g gas

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3 years ago
What is the molecular formula of the hydrocarbon whose molar mass is 536 g/mol and contains 89.55 w/w% carbon?
leonid [27]

Given the percentage composition of HC as C → 81.82 % and H → 18.18 %

So the ratio of number if atoms of C and H in its molecule can will be:

C : H = 81.82 12 : 18.18 1 C : H = 6.82 : 18.18 = 6.82 6.82 : 18.18 6.82 = 1 : 2.66 ≈ 3 : 8

So the Empirical Formula of hydrocarbon is:

C 3 H 8

As the mass of one litre of hydrocarbon is same as that of C O 2 The molar mass of the HC will be same as that of C O 2 i.e 44 g mol

Now let Molecular formula of the HC be ( C 3 H 8 ) n

Using molar mass of C and H the molar mass of the HC from its molecular formula is:

( 3 × 12 + 8 × 1 ) n = 44 n So 44 n = 44 ⇒ n = 1

Hence the molecular formula of HC is C 3 H 8

Does that help?

7 0
3 years ago
A cup of coffee has 71 mL of coffee and 127 mL of water. What is the percent volume of the coffee solution?
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Answer:

35.9%

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The percent volume of the coffee solution can be calculated as follows:

% volume of coffee solution = volume of coffee/total volume of coffee solution × 100

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71mL + 127mL = 198mL

% volume = 71/198 × 100

= 0.359 × 100

Percent volume of coffee solution = 35.9%

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