The metals are to the left of the line (except for hydrogen, which is a nonmetal), the nonmetals are to the right of the line, and the elements immediately adjacent to the line are the metalloids.
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Explanation:
The Order of Reaction refers to the power dependence of the rate on the concentration of each reactant.
The overall order of reaction is the sum of the individual orders of reaction with respect to the reactants.
Rate = k [A]²[B]¹
In the rate law above, the rate is second order with respect to A and first order with respect to B. The overall order of reaction is a third order reaaction given as; 2+ 1 = 3
Answer: The activation energy Ea for this reaction is 22689.8 J/mol
Explanation:
According to Arrhenius equation with change in temperature, the formula is as follows.
![ln \frac{k_{2}}{k_{1}} = \frac{-E_{a}}{R}[\frac{1}{T_{2}} - \frac{1}{T_{1}}]](https://tex.z-dn.net/?f=ln%20%5Cfrac%7Bk_%7B2%7D%7D%7Bk_%7B1%7D%7D%20%3D%20%5Cfrac%7B-E_%7Ba%7D%7D%7BR%7D%5B%5Cfrac%7B1%7D%7BT_%7B2%7D%7D%20-%20%5Cfrac%7B1%7D%7BT_%7B1%7D%7D%5D)
= rate constant at temperature 
= 
= rate constant at temperature 
= 
= activation energy = ?
R= gas constant = 8.314 J/kmol
= temperature = 
= temperature = 
Putting in the values ::
![ln \frac{4.8\times 10^8}{2.3\times 10^8} = \frac{-E_{a}}{8.314}[\frac{1}{649} - \frac{1}{553}]](https://tex.z-dn.net/?f=ln%20%5Cfrac%7B4.8%5Ctimes%2010%5E8%7D%7B2.3%5Ctimes%2010%5E8%7D%20%3D%20%5Cfrac%7B-E_%7Ba%7D%7D%7B8.314%7D%5B%5Cfrac%7B1%7D%7B649%7D%20-%20%5Cfrac%7B1%7D%7B553%7D%5D)
The activation energy Ea for this reaction is 22689.8 J/mol
Answer: The pull of the moon's gravity on Earth's water causes tidal bulges to form on the side closest to the moon and farthest from the moon. In the place where there are tidal bulges, high tide occurs along coastline.
Explanation:
Answer:
C) sp2 and sp2
Explanation:
The hybridization depens on the ammount and type of bonds the atom analized has in the molecule.
For example:
- A C atom bonded to 4 H atoms has a sp3 hybridization.
- A C atom bonded to 2 H atoms and to 1 C with a double bond (like in ethene) has a sp2 hybridization
- A C bonded to 1 H and 1 C with a triple bond (like in ethyne) has a sp hybridization.
Analyzing the type and amount of unions of the nitrogen and the carbonyl you will be able to determine the hybridization.
In the imine, the N atom has a double bond to a C and a simple bond two other C, plus the lone pair of electrons (counts as a bond) so it will have a sp2 hybridization.
In the carbonyl, the C has two simple bonds to other C and a double bond to an oxygen atom. It will also have a sp2 hybridization
