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Veseljchak [2.6K]
3 years ago
15

Two DNA sequences, each 48 kb in size, are treated with the same restriction enzyme. There is only one site for this restriction

enzyme on each of these sequences. Digests are separated by gel electrophoresis. Sequence A shows ONE band that is 48 kb in size. Sequence B shows TWO bands, one 30 kb and the other 18 kb in size What can you conclude from these data?
A. Sequence A is linear, sequence B is circular
B. Both sequences are linear. >X
C. They are identical sequences
D. Sequence A is circular, sequence B is linear
Chemistry
1 answer:
morpeh [17]3 years ago
7 0

Answer:

Sequence A is circular, sequence B is linear.

Explanation:

Restriction enzymes is also known as the molecular scissors that cuts the specific DNA fragments. Two main types of restriction enzymes are restriction exonuclease and restriction endonuclease.

The DNA fragments that are digested by the restriction endonuclease can be used for the preparation of the maps. The circular DNA ganaretes the equal number of fragments as it has the restriction site and linear DNA produce one extra fragments.

Thus, the correct answer is option (D).

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For the following reaction, 22.8 grams of diphosphorus pentoxide are allowed to react with 13.5 grams of water . diphosphorus pe
gavmur [86]

Answer:

m_{H_3PO_4}=31.5gH_3PO_4

Explanation:

Hello,

In this case, the undergoing chemical reaction is:

P_2O_5(s)+3H_2O(l)\rightarrow 2H_3PO_4(aq)

Thus, since the diphosphorus pentoxide to water molar ratio is 1:3 and we are given the mass of both of them, for the calculation of the maximum mass phosphoric acid that is yielded, one could first identify the limiting reactant, for which we compute the available moles of diphosphorus pentoxide (molar mass 142 g/mol):

n_{P_2O_5}=22.8gP_2O_5*\frac{1molP_2O_5}{142gP_2O_5}=0.161molP_2O_5

And the moles of diphosphorus pentoxide that are consumed by 13.5 g of water (molar mass 18 g/mol):

n_{P_2O_5}^{consumed}=13.5gH_2O*\frac{1molH_2O}{18gH_2O}*\frac{1molP_2O_5}{3molH_2O}  =0.25molP_2O_5

Hence, since less moles of diphosphorus pentoxide are available, we sum up it is the limiting reactant, therefore, the maximum mass of phosphoric acid (molar mass 98 g/mol) is computed by considering the 1:2 molar ratio between them as follows:

m_{H_3PO_4}=0.161molP_2O_5*\frac{2molH_3PO_4}{1molP_2O_5} *\frac{98gH_3PO_4}{1molH_3PO_4} \\\\m_{H_3PO_4}=31.5gH_3PO_4

Regards.

8 0
2 years ago
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