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Veseljchak [2.6K]
3 years ago
15

Two DNA sequences, each 48 kb in size, are treated with the same restriction enzyme. There is only one site for this restriction

enzyme on each of these sequences. Digests are separated by gel electrophoresis. Sequence A shows ONE band that is 48 kb in size. Sequence B shows TWO bands, one 30 kb and the other 18 kb in size What can you conclude from these data?
A. Sequence A is linear, sequence B is circular
B. Both sequences are linear. >X
C. They are identical sequences
D. Sequence A is circular, sequence B is linear
Chemistry
1 answer:
morpeh [17]3 years ago
7 0

Answer:

Sequence A is circular, sequence B is linear.

Explanation:

Restriction enzymes is also known as the molecular scissors that cuts the specific DNA fragments. Two main types of restriction enzymes are restriction exonuclease and restriction endonuclease.

The DNA fragments that are digested by the restriction endonuclease can be used for the preparation of the maps. The circular DNA ganaretes the equal number of fragments as it has the restriction site and linear DNA produce one extra fragments.

Thus, the correct answer is option (D).

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An activated complex has
nignag [31]
The answer is D higher potential energy and is unstable
8 0
2 years ago
A solution of phosphoric acid was made by dissolving 10.8 g of H3PO4 in 133.00 mL of water. The resulting volume was 137 mL. Cal
Nesterboy [21]

Answer:

Density is: 1.05 g/ml

Mole fraction solute: 0.015

Mole fraction solvent:  0.095

Molarity: 0.80 M

Molality: 0.82 m

Explanation:

A typical excersise of solution.

It is more confortable to make a table for this.

                |   masss  |  volume  |  mol

solute       |                |                |          

solvent     |                |                |  

solution    |                |                |

Let's complete, what we have.

                 |   masss  |  volume  |  mol

solute       |  10.8g     |                |          

solvent     |                |  133 mL   |  

solution    |                |  137 mL    |

We can first, know how many moles are 10.8 g

Molar Mass H3PO4 = 97.99 g/mol

Mass / Molar mass = mol

10.8 g / 97.99 g/m = 0.110 mol

Density of water is 1 g/ml (it is a very knowly value)

From this data, we can know water mass, solvent.

Density = mass / volume

1 g/ml = mass / 133 mL

Mass = 133 g

We can also have the moles, by the molar mass of water 18 g/m

133 g / 18 g/m = 7.39 mol

                 |   masss  |  volume  |  mol

solute       |   10.8g     |                |   0.110 mol      

solvent     |   133g      |  133 mL   |  7.39 mol

solution    |   143.8g   |  137 mL   | 7.50 mol

Mass of solution will be solute mass + solvent mass

Moles of solution will be solute moles + solvent moles

Now we can calculate everything.

Molarity means mol of solute in 1 L of solution. (mol/L)

We have to convert 137 mL in L (/1000)

0.137L so → 0.110 m / 0.137L = 0.80 M

Molality means mol of solute in 1kg of solvent.

We have to convert 133g in kg (/1000)

0.133 kg so → 0.110 m/0.133 kg = 0.82 m

Density is mass / volume

Solution density will be solution mass / solution volume

143.8 g/137 mL = 1.05 g/m

Molar fraction is : solute moles / total moles  or  solvent moles/total moles.

You can also (x 100%) to have a percent of them.

Remember sum of molar fraction = 1

Molar fraction of solute = 0.110 mol / 7.50mol = 0.015

Molar fraction of solvent = 7.39 mol / 7.50 mol = 0.985

5 0
3 years ago
Which one is more acidic, Chloroacetic acid or Bromoacetic acid? And why?
Mama L [17]

Chloroacetic acid <em>is stronger. </em>

<em>This is because it contains (more electronegative) chlorine atoms in place of (less electronegative) hydrogen atoms.</em>

3 0
3 years ago
If 14.5 g of MnO4- (permanganate) react with manganese (II) hydroxide how many grams of manganese (IV) oxide will be produced? T
Veronika [31]

Answer:

m_{MnO_2}=21.2gMnO_2

Explanation:

Hello,

In this case, given the balanced reaction:

2MnO_4^-+2Mn(OH)_2\rightarrow 4MnO_2+2OH^-+H_2O

We can see a 2:4 mole ration between permanganate ion (118.9 g/mol) and manganese (IV) oxide (86.9 g/mol), that is why the resulting mas of this last one turns out:

m_{MnO_2}=14.5gMnO_4^-*\frac{1molMnO_4^-}{118.9gMnO_4^-}*\frac{4MnO_2}{2molMnO_4^-}  *\frac{86.9gMnO_2}{1molMnO_2} \\\\m_{MnO_2}=21.2gMnO_2

Best regards.

5 0
3 years ago
(HELP ME ASAP!)
slega [8]
A) Ca(OH)2 + CO2 —> CaCO3 + H2O

B) when Ca(OH)2 is reacted with CO2, the CaCO3 produced is a precipitate which turns the solution milky
8 0
3 years ago
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