Which is an Element?<br><br> A. AIR<br> B. WATER<br> C. OXYGEN<br> D. CARBON DIOXIDE

a ball is thrown straight up into the air with a speed of 13 m/s. if the ball has a mass of 0.25 kg, how high does the ball go?

evablogger [386]

<h2>Hello!</h2>

The answer is: 8.62m

There are involved two types of mechanical energy: kinetic energy and potential energy, in two different moments.

<h2>First moment:</h2>

Before the ball is thrown, where the potential energy is 0.

<h2>Second moment: </h2>

After the ball is thrown, at its maximum height, the Kinetic Energy turns to 0 (since at maximum height,the speed is equal to 0) and the PE turns to its max value.

Therefore,

$E=PE+KE$

Where:

$PE=m.g.h$

$KE=\frac{1*m*v^{2}}{2}$

<em>E</em> is the total energy

<em>PE</em> is the potential energy

<em>KE</em> is the kinetic energy

<em>m</em> is the mass of the object

<em>g</em> is the gravitational acceleration

<em>h </em>is the reached height of the object

<em>v</em> is the velocity of the object

Since the total energy is always constant, according to the Law of Conservation of Energy, we can write the following equation:

$KE_{1}+PE_{1}=KE_{2}+PE_{2}$

Remember, at the first moment the PE is equal to 0 since there is not height, and at the second moment, the KE is equal to 0 since the velocity at maximum height is 0.

$\frac{1*m*v^{2}}{2}+m.g.(0)=\frac{1*m*0^{2}}{2}+m.g.h\\\frac{1*m*v_{1} ^{2}}{2}=m*g*h_{2}$

So,

$h_{2}=\frac{1*m*v_{1} ^{2}}{2*m*g}\\h_{2}=\frac{1*v_{1} ^{2}}{2g}=\frac{(\frac{13m}{s})^{2} }{2*\frac{9.8m}{s^{2}}}\\h_{2}=8.62m}$

Hence,

The height at the second moment (maximum height) is 8.62m

Have a nice day!

5 0

4 years ago

Circular coil 1 has N turns and circular coil 2 has 6N. Coil 1 has area A and coil 2 has area A/4. If Coil 1 has current i runni

solmaris [256]

Answer:

$\frac{L_1}{L_2} =\frac{1}{3}$

Explanation:

Recall that the formula for an inductance (L) for coil on N turns, are A and current I is given by:

$L=\frac{\mu_0\,N^2\,A}{I}$

Then, for the first coil we have;

$L_1=\frac{\mu_0\,N^2\,A}{I}$

and for coil 2 we have:

$L_2=\frac{\mu_0\,(6\,N)^2\,(A/4)}{3\,I}$

then, the quotient L1/L2 can be written as:

$\frac{L_1}{L_2} =\frac{\mu_0\,N^2\,A\,3\,I}{\mu_0\,(6\,N)^2\,(A/4)\,I}=\frac{12}{36} =\frac{1}{3}$

7 0

3 years ago

If the angle of incidence of a light source to a shiny surface is 30 degrees, what will the angle

Virty [35]

<h3>Answer: D) 30</h3>

Angle of incidence always equals angle of reflection. Think of a tennis ball being hit into a wall. The ball will bounce off at the same angle that it approached with. The angles mentioned are formed through the line called the "normal", which is the line perpendicular to the surface.

5 0

3 years ago

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How much work does a 65 kg gymnast have to do to climb a rope to a height of 7? meters? PLEASE HURRY ITS A TEST

Karo-lina-s [1.5K]

How much force did the gymnast use to climb the rope?

4 0

3 years ago

4. There is a flashing yellow light at the intersection you are approaching. What does the flashing yellow light indicate, and w

OleMash [197]

It indicates that you should proceed with caution. You should slow down and be prepared to stop to safely navigate this intersection.

4 0

4 years ago

Which is an Element? A. AIR B. WATER C. OXYGEN D. CARBON DIOXIDE