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Nostrana [21]
3 years ago
11

A steel ball is dropped from a building's roof and passes a window, taking 0.12 s to fall from the top to the bottom of the wind

ow, a distance of 1.20 m. It then falls to a sidewalk and bounces back past the window, moving from bottom to top in 0.12 s. Assume that the upward flight is an exact reverse of the fall. The time the ball spends below the bottom of the window is 1.76 s. How tall is the building?
Physics
1 answer:
Dvinal [7]3 years ago
8 0
The top of the WINDOW is 19 meters from the ground. also steel balls dont bounce.
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Write a balanced equation for the decomposition of ammonium nitrate to form molecular nitrogen, molecular oxygen, and water. Exp
VARVARA [1.3K]

The unbalanced reaction is

<em>a</em> NH₄NO₃   ⇒   <em>b</em> N₂ + <em>c</em> O₂ + <em>d</em> H₂O

where <em>a</em>, <em>b</em>, <em>c</em>, and <em>d</em> are unknown constants.

Count how many times each element appears on either side of the reaction.

• reactants:

N = 2<em>a</em>, H = 4<em>a</em>, O = 3<em>a</em>

• products

N = 2<em>b</em>, O = 2<em>c</em> + <em>d</em>, H = 2<em>d</em>

<em />

Now we solve the system of equations,

2<em>a</em> = 2<em>b</em> … … … [1]

4<em>a</em> = 2<em>d</em> … … … [2]

3<em>a</em> = 2<em>c</em> + <em>d</em> … … … [3]

<em />

From [1] we immediately have

<em>a</em> = <em>b</em>

In [2], we get

2<em>a</em> = <em>d</em>

and substituting for <em>d</em> in [3] gives

3<em>a</em> = 2<em>c</em> + 2<em>a</em>

<em>a</em> = 2<em>c</em>

<em />

Let <em>c</em> = 1; then

• <em>a</em> = 2×1 = 2

• <em>b</em> = 2

• <em>d</em> = 2×2 = 4

So, the balanced reaction is

2 NH₄NO₃   ⇒   2 N₂ + O₂ + 4 H₂O

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What kind of scattering (Rayleigh, Mie, or non-selective) would you expect to be most important when radiation of the specified
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Answer:

hello your question is not properly arranged attached below is the arranged table and solution

answer : attached table below

Explanation:

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Attached below is a table showing the kind of scattering that is expected to occur at various wave lengths

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and  For Mie scattering the wavelength is the same as the wavelength.

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