Question

3.A golf ball is hit of it’s tee, 200m down the fairway.

Answer 1

Answers:

3. The diagrams showing the forces acting on the golf ball are in the figure attached. Let’s have a detailed look:

a) Here the ball is under 2 forces:

F1 which is called The Normal force and is perpendicular to the surface of the tee where the ball rests

-F1, related to the gravity force, to the weight of the ball, and has the same magnitude, but the opposite direction (That’s why it has a negative sign).

In this case the sum of the forces is 0

b) Here we have again forces F1 and –F1, but in this very moment the club strikes the ball and we have:

F2, the force of the strike

c) While the ball is in its flight, it is under the following forces:

F1, the force of the lift through the air

-F2, the gravity force

-F3, the force of air resistance, also called drag

F4, the tangencial force of the ball flight

4. Here are the sizes and directions of the resultant forces:

i)Two forces of the same magnitude or size are applied to this block, but in opposite directions (in the x-axis). This is expressed as:

F=-10N+10N=0 The resulting force is zero

ii) Two forces of different size and opposite directions in the y-axis are applied to this block. The sum of the forces is:

F=30N-40N=-10N This means the resulting force is 10N applied downwards

iii) In this case the only force applied to the block is -5N applied downwards

iv) Here there are four forces applied to the block.  

In the y-axis we have to forces of the same size but opposite directions:

F1=10N-10N=0 This means the applied force in the y-axis is zero

In the x-axis we have two forces of different size and opposite directions:

F2=-15N+10N=-5N This means the resulting force is applied to the –x-side