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3 years ago

7

Dilute hydrochloric acid is gradually added to a solution that is buffered at pH 4.76. How will the pH of the solution be affect

ed?

1 answer:

Igoryamba3 years ago

6 0

Answer:

Adding acid to any buffer solution will cause the pH to decrease

Explanation:

Adding acid to buffer solutions is increasing the H⁺ concentration and therefore causes the pH to decrease.

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Quarks are<br> A A Fact<br> B Fiction<br> C Both of the above<br> D Neither of the above

stiks02 [169]

I’d say A. They are theoretical in the fact that they have not been observed directly, but have been confirmed to exist through experimentation.

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3 years ago

Is Naci a metal or none metel

Schach [20]

Answer:

Salt (NaCl) is an ionic bond that consists of Sodium (Na) which is a metal with positive charge combines with Chlorine (Cl), a nonmetal with a negative charge.

Explanation:

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3 years ago

Select all of the following statements that represent the differences between a voltaic cell and an electrolytic cell. Group of

Sunny_sXe [5.5K]

Answer:

The electrodes will change in mass for only the electrolytic cell

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3 years ago

20 mL of Ba(OH)2 solution with unknown concentration was neutralized by the addition of 43.89 mL of a .1355 M HCl solution. Calc

bezimeni [28]

Answer:

Concentration of the barium ions = $[Ba^{2+}] = 0.4654 M$

Concentration of the chloride ions = $[Cl^{-}]=0.9308 M$

Explanation:

$Moles (n)=Molarity(M)\times Volume (L)$

Moles of hydrogen chloride = n

Volume of hydrogen chloride solution = 43.89 mL = 0.04389 L

Molarity of the hydrogen chloride = 0.1355 M

$n=0.1355 M\times 0.04389 L=0.005947 mol$

$Ba(OH)_2+2HCl\rightarrow BaCl_2+2H_2O$

According to reaction, 2 moles of HCl reacts with 1 mole of barium hydroxide.

Then 0.05947 moles of HCl will react with:

$\frac{1}{2}\times 0.05947 mol=0.029735 mol$ barium hydroxide

Moles of barium hydroxide = 0.029735 mol

$Ba(OH)_2(aq)\rightarrow Ba^{2+}(aq)+2OH^-(aq)$

1 mole of barium hydroxide gives 1 mole of barium ion in an aqueous solution. Then 0.029735 moles of barium hydroxide will give:

$=1\times 0.029735 mol= 0.029735 mol$

Volume of solution after neutralization reaction :

= 20.0 mL + 43.89 mL = 63.89 mL = 0.06389 L

Concentration of the barium ions = $[Ba^{2+}]$

$[Ba^{2+}]=\frac{0.029735 mol}{0.06389 L}=0.4654 M$

$Ba(Cl)_2(aq)\rightarrow Ba^{2+}(aq)+2Cl^-(aq)$

1 mole of barium chloride gives 1 mole of barium ions and 2 moles of chloride ions in an aqueous solution.

Then concentration of chloride ions will be:

$[Cl^-]=2\times [Ba^{2+}]=2\times 0.4654 M=0.9308 M$

8 0

3 years ago

What volume of a 5.00M solution of hydrochloric acid contains 8.00mol of HCl?

rjkz [21]

Answer:

520ML and apparently I need to put more in this answer

Explanation:

brainly.com

7 0

3 years ago