Answer:
2NO(g) + O2(g) ---> 2NO2(g)
Explanation:
The mechanism for this reaction involves two elementary reactions in which both are bimolecular as shown below;
NO(g) +O2(g) ----> NO2(g) + O(g)
NO(g) + O(g) ----> NO2(g)
Hence overall balanced reaction equation;
2NO(g) + O2(g) ---> 2NO2(g)
Answer:
Explanation:
By definition, <em>half neutralization</em> is the point at which half of the acid has been neutralized.
The neutralization reaction that you are studying is the acid-base reaction:
- HCl (aq) + NaOH (aq) → NaCl(aq) + H₂O (aq)
Then, since the starting molarity of the acid (HCl) is 0.2 M, you just need to find half of that concentration:
- Half molarity = M / 2 = 0.2 M / 2 = 0.1 M
So, the answer is the first choice: a. 0.1 M.
Answer:
N - 1s²2s²2p³
Explanation:
Nitrogen is located in the p-block of the periodic table (groups 13-18) and is on the 2nd period.
The 2nd period tells us the principal energy level (a quantum number) is n = 2. Therefore, it must have already filled up the 1s sublevel.
The groups 13-18 on period 2 tells us that the 2s sublevel is also filled.
Nitrogen is located in Group 15. That means that there are 3 electrons that have filled the 2p sublevel, out of a possible 6.
Therefore, our electron configuration is 1s²2s²2p³
2p³ (Shorthand Config)
[He] 2s²2p³ (Noble Gas Config)
The Freezing point is ALWAYS the same as the melting point,even for different elements. 6,422 is its melting,and freezing point. Same with gold,iron,hydrogen,and many others
Answer:
B) -1551 kJ
Explanation:
There are two heat flows in this question.
Heat released by engine + heat absorbed by water = 0
q₁ + q₂ = 0
q₁ + mCΔT = 0
Data:
m = 2.51 kg
C = 3.41 J°C⁻¹g⁻¹
T_i = 23.8 °C
T_f =205 °C
Calculations:
(a) ΔT
ΔT = 205 °C - 23.8 °C = 181.2 °C
(b) q₂
q₂ = mCΔT = 2510 g × 3.41 J·°C⁻¹g⁻¹ × 181.2 °C = 1.551× 10⁶ J = 1551 kJ
(c) q₁
q₁ + 1551 kJ = 0
q₁ = -1551 kJ
