Answer:
1.935 mole
Explanation:
We'll begin by calculating the number of mole present in 3.88x10^23 molecules of nitrogen(N2). This can be obtained as follow:
From Avogadro's hypothesis, 1 mole of any substance contains 6.02x10^23 molecules. Therefore 1 mole of N2 contains 6.02x10^23 molecules.
Now if 1 mole of N2 contains 6.02x10^23 molecules,
Then Xmol of N2 will contain 3.88x10^23 molecules i.e
Xmol of N2 = (3.88x10^23)/6.02x10^23
Xmol of N2 = 0.645 mole
Now, we can obtain the number of moles of PbO required to generate 3.88x10^23 molecules (i.e 0.645 mole) of N2. This is illustrated below:
The equation for the reaction is given below:
3PbO + 2NH3 → 3Pb + N2 + 3H2O
From the balanced equation above, 3 moles of PbO produced 1 mole of N2.
Therefore, Xmol of PbO will produce 0.645 mole of N2 i.e
Xmol of PbO = 3 x 0.645
Xmol of PbO = 1.935 mole.
From the calculations made above,
1.935 mole of PbO will produce 3.88x10^23 molecules of nitrogen (N2).
