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Deffense [45]
3 years ago
8

A certain metal M crystallizes in a lattice described by a body-centered cubic (bcc) unit cell. The lattice constant (a, the edg

e of the unite cell) has been measured by X-ray crystallography to be 360. pm. Calculate the radius of an atom of M. Be sure your answer has 3 significant digits, and be sure it has the correct unit symbol.
Chemistry
1 answer:
Furkat [3]3 years ago
3 0

Answer:

radius = 156 pm

Explanation:

The relation between radius and edge length of unit cell of BCC is

r=a\sqrt{3}/4

Given

a = 360 pm

Therefore

r = r = radius = 360\sqrt{3}/4= 155.88 pm

Or

156 pm

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levacccp [35]

Answer:

salt dissolving

Explanation:

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2 years ago
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How many molecules of sugar (C6H1206) are in a mole?
Tanzania [10]
By definition, one mole (one gram molecular weight) of any substance, contains Avogadro’s number of particles; atoms if you are discussing an element, or molecules if a compound. Avogadro’s number has been determined by several methods, all of the accepted values lie within a range of +-1% about the value of 6.022045 x 10^23/gm. That is a large number, in this case approximately; 602,204,500,000,000,000,000,000 molecules of glucose.

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8 0
3 years ago
What is the concentration of a 1:10 dilution of a 2.5 M solution of NaCl? How would you prepare exactly 100 ml of such a solutio
Marina CMI [18]

<u>Answer:</u> The concentration of the solution is 0.25 M

<u>Explanation:</u>

Let the volume of solution of 2.5 M NaCl be 10 mL

We are given:

Dilution ratio = 1 : 10

So, the solution prepared will have a volume of = \frac{10}{1}\times 1000=100mL

To calculate the molarity of the diluted solution, we use the equation:

M_1V_1=M_2V_2

where,

M_1\text{ and }V_1 are the molarity and volume of the concentrated NaCl solution

M_2\text{ and }V_2 are the molarity and volume of diluted NaCl solution

We are given:

M_1=2.5M\\V_1=10mL\\M_2=?M\\V_2=100mL

Putting values in above equation, we get:

2.5\times 10=M_2\times 100\\\\M_2=\frac{2.5\times 10}{100}=0.25M

Hence, the concentration of the solution is 0.25 M

6 0
3 years ago
Select all that apply.
Ilya [14]
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5 0
3 years ago
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7. Diethyl ether burns in air according to the following equation. C4H10O(l) + 6O2 (g) → 4CO2 (g) + 5H2O(l) If 7.15 L of CO2 is
iren [92.7K]

From the stoichiometry of the combustion reaction, we can see that 7.4 L of oxygen is consumed.

<h3>What is combustion?</h3>

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We can obtain the number of moles of CO2 from;

PV = nRT

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If 6 moles of oxygen produces 4 moles of CO2

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x = 0.33  moles

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0.33 moles of oxygen occupies 0.33 moles *  22.4 L/ 1 mole

= 7.4 L of oxygen

Learn more about stoichiometry: brainly.com/question/13110055

#SPJ1

6 0
2 years ago
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