Question

What will the pressure be if 89.9 moles of argon are contained in a 12.0 L cylinder that is pressurized at a temperature of 300 K?

Answer 1

• P=nRT/V
• p=89.9(8.314)(12)/300
• P=8969.14/300
• P=29.89atm
• P=29.9atm

Done!