Answer:
If a net horizontal force of 175 N is applied to a bike whose mass is 43 kg what acceleration is produced? What average net force is ... A 10,000 N net force is accelerating a car at a rate of 5.5 m/s2. What is the car's mass? A boy pedals his ...
Explanation:
Yes, Sliding friction opposes the movement of the book, slowing it down.sliding That's the 'kinetic' kind.. According to Newton's second law, F=ma. That is, the bear's acceleration should be proportional to the total force acting on the bear. As the bear's velocity is constant, its acceleration is zero. Therefore, the total Force acting on the bear is zero. Thus, the friction has to be equal in magnitude and opposite in direction to the bear's weight. As W=mg, we get that its weight is <span>9.8*400=3,920 Newton. Thus, the friction acting on the bear is 3,920 Newton</span>
** Missing information: The vertical distance from surface of liquid to bottom of the object is sought in this question, with the condition that the object is at equilibrium **
Ans: The vertical distance = y = M/(ρA)
Explanation:Support the vertical distance = y
Object's density = M/(A*h) (since A*h = volume)
By applying the condition,
(M/(Ah))/ρ = y/h
M/(ρAh) = y/h
y = M/(ρA)
Answer:
1788.402 MJ
Explanation:
Work done = Force (N) x distance (m)
First we have to convert distance into metres:
173.8 x 1000 = 173,800 m
Then plug these values into the equation above:
173,800 x 10290 = 1788402000 J
The reason it's Joules (the unit for energy) is because work done = energy transferred
Now we have to convert Joules into Mega Joules:
1 J = 1/1000000 MJ
1788402000 J = 1788402000/ 1000000 = 1788.402 MJ
Answer:
The coconut hit the ground after 1.28 s
Explanation:
Velocity: This can be defined as the rate of change of displacement. Or it is defined as speed in a specified direction. Velocity is a vector quantity. The S.I unit of velocity is m/s.
Using the equation of motion,
S = ut + 1/2gt²....................................... Equation 1
Where S = distance, u = initial velocity, t = time, g = acceleration due to gravity
<em>Given: s= 8 m, u = 0 m/s ( because it was drop from a height), </em>
<em>Constant : g = +9.8 m/s²</em>
<em>Substituting these values into equation 1,</em>
<em>8 = 0×t + 1/2(9.8×t²)</em>
<em>8 = 4.9t²</em>
<em>t² = 8/4.9</em>
<em>t = √1.63</em>
<em>t = 1.276 s</em>
t = 1.28 s
Therefore the coconut hit the ground after 1.28 s
