All categories

3 years ago

The Sun keeps all of the planets orbiting it because _____.

2 answers:

6 0

<span>A, The law of universal gravitation states that an increase in mass causes an increase in gravitational force. For this reason, the sun keeps all the planets in orbit because this classical and physical law describes the gravitational interaction between bodies.</span>

Nuetrik [128]3 years ago

4 0

The law of universal gravitation because it was right on my test.

You might be interested in

One way to describe a wave crest is the amount of ___________ applied over an area.

Pani-rosa [81]

I believe it’s force but i’m not really sure.

8 0

3 years ago

Read 2 more answers

At left A red ball in a box with arrows pointing away from the ball in all directions. In the middle, a blue ball in a box with

MAVERICK [17]

Answer:

first one is b 2nd one is a 3rd is c and the 4th one is c also

Explanation: have a nice day

6 0

2 years ago

Read 2 more answers

How many protons are in this atom if it has a balanced charge? 0 2 4 6

pickupchik [31]

Answer:

For an atom to have a balanced charged, the number of protons shall be equal to the number of electrons of an atom. proton is the positive part of an atom whereas electrons are the negative part of an atom. Only if the number of protons will be equal to the number of electron, the atom will be able to be neutral.

If the number of electron will be more, then the atom will be negative. If the number of electron will be less, then the atom will be positive.

7 0

3 years ago

Read 2 more answers

The free-fall acceleration on Mars is 3.7 m/s^2. What length of pendulum has a period of 1.0 s on Earth? What length of pendulum

NemiM [27]

Answer:

Explanation:

Given

Free fall acceleration on mars $g_{m}=3.7\ m/s^2$

Time Period of pendulum on earth $T=1\ s$

Time period of Pendulum is given by

$T=2\pi \sqrt{\frac{L}{g}}$

for earth

$1=2\pi\cdot \sqrt{\frac{L}{9.8}}$

$L=\frac{9.8}{(2\pi )^2}$

$L=0.498\ m$

(b)For same time period on mars length is given by

$L'=\frac{g_m}{(2\pi )^2}$

$L'=\frac{3.7}{39.48}$

$L'=0.0936\ m$

$L'=9.36\ cm$

3 0

4 years ago

A simple harmonic oscillator completes 1550 cycles in 30 min. (a) Calculate the period. s (b) Calculate the frequency of the mot

nordsb [41]

Answer:

(a) 1.16 s

(b)0.861 Hz

Explanation:

(a) Period : The period of a simple harmonic motion is the time in seconds, required for a object undergoing oscillation to complete one cycle.

From the question,

If 1550 cycles is completed in (30×60) seconds,

1 cycle is completed in x seconds

x = 30×60/1550

x = 1.16 s

Hence the period is 1.16 seconds.

(b) Frequency : This can be defined as the number of cycles that is completed in one seconds, by an oscillating body. The S.I unit of frequency is Hertz (Hz).

Mathematically, Frequency is given as

F = 1/T ........................... Equation 1

Where F = frequency, T = period.

Given: T = 1.16 s.

Substitute into equation 1

F = 1/1.16

F = 0.862 Hz

Hence thee frequency = 0.862 Hz

6 0

3 years ago