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2 years ago

15

The Sun keeps all of the planets orbiting it because _____.

2 answers:

Lelu [443]2 years ago

6 0

<span>A, The law of universal gravitation states that an increase in mass causes an increase in gravitational force. For this reason, the sun keeps all the planets in orbit because this classical and physical law describes the gravitational interaction between bodies.</span>

Nuetrik [128]2 years ago

4 0

The law of universal gravitation because it was right on my test.

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Block A is also connected to a horizontally-mounted spring with a spring constant of 281 J/m2. What is the angular frequency (in

Svetradugi [14.3K]

Answer:

This question is incomplete

Explanation:

This question is incomplete. However, the formula to be used here is

ω = 2π/T

Where ω is the angular frequency (in rad/s)

T is the period - the time taken for Block A to complete one oscillation and return to it's original position.

To solve for this period T, the formula below should be used

T = 2π√m/k

where m is the mass of the object (Block A) and k is the spring constant (281 J/m²)

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2 years ago

Microscopes are often equipped with blue filters. give a reason for using blue light in a microscope

timama [110]

The blue light removes red parts of the color spectrum giving it a cooler color

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3 years ago

What roles do the musk ox play in the tundra ecosystem? (Select all that apply.)

docker41 [41]

Answer:

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2 years ago

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If Chris drives 27 km N and then 40 km E , what is the distance and displacement

Bas_tet [7]

The answer would be 13.

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3 years ago

The potential at location A is 382 V. A positively charged particle is released there from rest and arrives at location B with a

jarptica [38.1K]

Answer: 247.67 V

Explanation:

Given

Potential At A $V_a=382\ V$

Potential at $V_c=785\ V$

when particle starts from A it reaches with velocity $v_b$ at Point while when it starts from C it reaches at point B with velocity $2v_b$

Suppose m is the mass of Particle

Change in Kinetic Energy of particle moving under the Potential From A to B

$q\cdot \left ( V_a-V_b\right )=0.5m\cdot (v_b)^2----1$

Change in Kinetic Energy of particle moving under the Potential From C to B

$q\cdot \left ( V_c-V_b\right )=0.5m\cdot (2v_b)^2-----2$

Divide 1 and 2 we get

$\frac{V_a-V_b}{V_c-V_b}=\frac{v_b^2}{4v_b^2}$

on solving we get

$V_b=\frac{4}{3}\cdot V_a-\frac{1}{3}\cdot V_c$

$V_b=\frac{743}{3}=247.67\ V$

4 0

3 years ago