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Nikolay [14]
3 years ago
5

What is the % error in using g = 10.0 m/s^2? (Take the value ofg as 9.8 m/s^2)

Physics
1 answer:
Alenkasestr [34]3 years ago
4 0

Answer:

So percentage error will be 2 %

Explanation:

We have given initial value of acceleration due to gravity g=10m/sec^2

And final value of acceleration due to gravity g=9.8m/sec^2

We have to find the percentage error

We know that percentage error is given by percentage\ error=\frac{initial\ value-final\ value}{initial\ value}\times 100

So percentage\ error=\frac{10-9.8}{10}\times 100=2 %

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3 years ago
For an object to be classified as a ____, it must meet certain definite criteria: It must be massive enough to pull itself into
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Answer:

a planet

Explanation:

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Extra:

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6 0
3 years ago
Read 2 more answers
A vw beetle goes from 0 to 60 mi/h with an acceleration of 2.35 m/s^2.
Vlad1618 [11]
Part a.
u = 0, the initial velocity
v = 60 mi/h, the final velocity
a = 2.35 m/s², the acceleration.

Note that
1 m = 1609.34 m.
Therefore
v = (60 mi/h)*(1609.34 m/mi)*(1/3600 h/s) = 26.822 m/s
Use the formula
v = u + at
(26.822 m/s) = (2.35 m/s²)*(t s)
t = 26.822/2.35 = 11.4 s

Answer: 11.4 s

Part b.
We already determined that v = 60 mi/h = 26.822 m/s.
t = 0.6 s
Therefore
(26.822 m/s) = (a m/s²)*(0.6 s)
a = 26.822/0.6 = 44.7 m/s²

Answer:  44.7 m/s²
6 0
3 years ago
If the work required to move a 0.35 c charge from point a to point b is 125 j, what is the potential difference between the two
valentina_108 [34]
Using W = qV  =>  V = W/q


7 0
3 years ago
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