Answer:
<h2>153J</h2>
Explanation:
Step one:
given data
mass m= 8.5kg
radius r= 10cm in meters = 0.01m
velocity v= 6m/s
The work done will be the same as the energy possessed by the sphere at such speed
Required
the work one in Joules
we know that
KE=1/2mv^2
KE=1/2*8.5*6^2
KE= 1/2*8.5*36
KE=306/2
KE=153J
Explanation:
Given data
Inductance L=12*10^-³H
Capacitance C= 3.5*10^-6F
Resistance R= 3.3 Ohms
Voltage V=115v
Capacitive reactance Xc=?
inductive reactance Xl=?
Impedance Z=?
Phase angle =?
A. Resonance frequency
In RLC circuit resonance occurs when capacitive reactance equals inductive reactance
f=1/2pi √ LC
f=1/2*3.142 √ 12*10^-³*3.5*10^-6
f=1/6.284*0.0002
f=1/0.00125
f=800HZ
B. Find Irms at resonance.
Irms=R/V
Irms=3.3/115
Irms=0.028amp
Find the capacitive reactance XC in Ohms
Xc=1/2pi*f*C
Xc=1/2*3.142*800*3.5*10^-6
Xc=1/0.0176
Xc=56.8 ohms
To find the inductive reactance
Xl=2pifL
Xl=2*3.142*800*12*10^-3
Xl=60.3ohms
d) Find the impedance Z.
Z=√R²+(Xl-Xc)²
Z=√3.3²+(60.3-56.8)²
Z=√10.89+12.25
Z=√23.14
Z=4.8ohms
Phase angle =
Tan phi=Xc/R=56.8/3.3
Tan phi=17.2
Phi=tan-1 17.2
Phi= 1.51°
The wheel and axle increases your force. You exert your input force over a long distance and the output force is increased over a shorter distance. (Because the wheel is larger than the axle, the axle rotates and exerts a large output force.) A simple machine with a grooved wheel with a rope or cable wrapped around it.
Answer:
your answer would be D because the waves results from back n forth vibrations of the particles of the medium throught which the sound waves is moving .
If the separation distance is doubled, then the electric field decreases by a factor of 4.
<h3>What is the electric field strength?</h3>
We know that the electric field strength is known to depend on the magnitude of the charge and the distance of separation. We know that the electric field refers to the region in which the influence of a charge is felt. Recall that a charge is a specie that is positively or negatively charged. The charge on a specie must always be shown by its sign.
We know that the electric field is the region in space where the influence of a charge can be felt. If a charge is placed in the vicinity of another charge, the second charge would experience a force due to the presence of the first charge. This is because the second charge was brought into the electric field of the first charge.
Thus we know that;
E = Kq/r^2
Where;
E = electric field strength
q = magnitude of charge
r = distance of separation
Now;
E = 9.0* 10^9 * 3.052 * 10^-6/(8.22 * 10^-2)^2
E = 4 N/C
Given that the electric filed strength is inversely proportional to the distance of separation, when the distance between the charges is doubled, the electric field decreases by a factor of 4.
Learn more about electric field strength:brainly.com/question/15170044?
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