Answer:
The final velocity of the second car is 57 m/s south.
Explanation:
This is an elastic collision between two train cars. In this case, the total kinetic energy between the two bodies will remain the same.
The formula to apply is :
![m_1v_1i +m_2v_2i=m_1v_1f+m_2v_2f](https://tex.z-dn.net/?f=m_1v_1i%20%2Bm_2v_2i%3Dm_1v_1f%2Bm_2v_2f)
where ;
![m_1=mass of object 1\\v_1i=initial velocity object1\\m_2=mass of object2\\v_2i=initial velocity object 2\\v_1f=final velocity object 1\\v_2f=final velocity object 2](https://tex.z-dn.net/?f=m_1%3Dmass%20of%20object%201%5C%5Cv_1i%3Dinitial%20%20velocity%20object1%5C%5Cm_2%3Dmass%20of%20object2%5C%5Cv_2i%3Dinitial%20velocity%20object%202%5C%5Cv_1f%3Dfinal%20velocity%20object%201%5C%5Cv_2f%3Dfinal%20velocity%20object%202)
Given in the question that;
![m_1=14650kg\\v_1i=18m/s\\m_2=3825kg\\v_2i=11m/s\\v_1f=6m/s\\v_2f=?](https://tex.z-dn.net/?f=m_1%3D14650kg%5C%5Cv_1i%3D18m%2Fs%5C%5Cm_2%3D3825kg%5C%5Cv_2i%3D11m%2Fs%5C%5Cv_1f%3D6m%2Fs%5C%5Cv_2f%3D%3F)
Apply the formula as;
![m_1v_1i +m_2v_2i=m_1v_1f+m_2v_2f](https://tex.z-dn.net/?f=m_1v_1i%20%2Bm_2v_2i%3Dm_1v_1f%2Bm_2v_2f)
{14650*18}+{3825*11} = {14650 *6} + {3825 * v₂f}
263700+42075=87900 + 3825v₂f
305775 =87900 + 3825v₂f
305775-87900 = 3825v₂f
217875=3825v₂f
217875/3825 =v₂f
56.96 = v₂f
<u>57 m/s = v₂f { nearest whole number}</u>
Answer:
ΔT = 0.02412 s
Explanation:
We will simply calculate the time for both the waves to travel through rail distance.
FOR THE TRAVELING THROUGH RAIL:
![T_{rail} = \frac{Distance}{Speed\ of\ Sound\ in\ Rail}\\\\T_{rail} = \frac{8.8\ m}{5950\ m/s}\\\\T_{rail} = 0.00148\ s](https://tex.z-dn.net/?f=T_%7Brail%7D%20%3D%20%5Cfrac%7BDistance%7D%7BSpeed%5C%20of%5C%20Sound%5C%20in%5C%20Rail%7D%5C%5C%5C%5CT_%7Brail%7D%20%3D%20%5Cfrac%7B8.8%5C%20m%7D%7B5950%5C%20m%2Fs%7D%5C%5C%5C%5CT_%7Brail%7D%20%3D%200.00148%5C%20s)
FOR THE WAVE TRAVELING THROUGH AIR:
![T_{air} = \frac{Distance}{Speed\ of\ Sound\ in\ Air}\\\\T_{air} = \frac{8.8\ m}{343\ m/s}\\\\T_{air} = 0.0256\ s](https://tex.z-dn.net/?f=T_%7Bair%7D%20%3D%20%5Cfrac%7BDistance%7D%7BSpeed%5C%20of%5C%20Sound%5C%20in%5C%20Air%7D%5C%5C%5C%5CT_%7Bair%7D%20%3D%20%5Cfrac%7B8.8%5C%20m%7D%7B343%5C%20m%2Fs%7D%5C%5C%5C%5CT_%7Bair%7D%20%3D%200.0256%5C%20s)
The separation in time between two pulses can now be given as follows:
![\Delta T = T_{air}-T_{rail} \\\Delta T = 0.0256\ s - 0.00148\ s\\](https://tex.z-dn.net/?f=%5CDelta%20T%20%3D%20T_%7Bair%7D-T_%7Brail%7D%20%5C%5C%5CDelta%20T%20%3D%200.0256%5C%20s%20-%200.00148%5C%20s%5C%5C)
<u>ΔT = 0.02412 s</u>
Answer:
7 / 1
Explanation:
The ratio of their amplitude = one-seventh and the ratio of their amplitude = the ratio of their wavelength
Ax / Ay = λx / λy = 1 / 7
λy / λx = 7 / 1
Sup Milk,
Sublimation = Energy is absorbed and a solid turns to a gas.
Condensation = Energy is released and a gas changes to a liquid.
Evaporation = Energy is absorbed into a liquid to turn it into a gas.