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Rasek [7]
3 years ago
13

Consider this situation: A rope is used to lift an actor upward off the stage. Of the forces listed, identify which act upon the

actor.
Normal


Gravity


Applied


Friction


Tension


Air Resistance
Physics
2 answers:
zhenek [66]3 years ago
6 0
Gravity, and air resistance act upon the actor.
sveticcg [70]3 years ago
4 0

Answer:

Gravity

Tension

Air Resistance

Explanation:

Since actor is lifted upwards with the help of rope which is connected to the actor

so here forces that will act upon it

1) Gravity

Gravity is due to gravitational force of earth which will act towards center of earth or vertically downwards

2) Tension

This is a type of electromagnetic force which will act along the string and it will help the actor to balance against his weight

3) Air Resistance

this is due to friction of air which will act opposite to the motion of actor in air

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The y-axis on a distance-time graph would be ____________. time distance speed
natita [175]

Answer:

Distance

Explanation:

distance is in vertical axis,or y-axis and time is on the horizontal axis,or x-axis.

7 0
3 years ago
At the county fair, Chris throws a 0.12kg baseball at a 2.4kg wooden milk bottle, hoping to knock it off its stand and win a pri
viva [34]

Answer:

v_{f2} =6.5%v_{i1}

Explanation:

Mass of the ball: m_{1} =0.12kg]

Initial velocity of the ball:   v_{i1}

final velocity of the ball: v_{f1} which is -30/100 of v_{i1} =-0.3v_{i1}

Mass of the bottle: m_{2} =2.4kg

Initial velocity of the bottle: v_{i2}=0m/s

final velocity of the bottle: v_{f2} is unknown (to find)

<em>by using conservation momentum, which stated that the initial momentum is equal to the final momentum.</em>

<em />m_{1} v_{i1} +m_{2} v_{i2} =m_{1} v_{f1} +m_{2} v_{f2}<em />

<em>so since the bottle is at rest firstly, therefore </em>v_{i2} =0<em />

<em />m_{1} v_{i1} +m_{2} (0) =m_{1} v_{f1} +m_{2} v_{f2}<em />

<em />m_{1} v_{i1}  =m_{1} v_{f1} +m_{2} v_{f2}<em>         </em><em>equation 1</em>

so now substitute v_{f1} into equation 1

m_{1} v_{i1}  =m_{1} (-0.3v_{i1} ) +m_{2} v_{f2}

<em />m_{1} v_{i1}  = -0.3m_{1}v_{i1}  +m_{2} v_{f2}<em />

<em>collect the like terms</em>

m_{1} v_{i1}   +0.3m_{1}v_{i1}  =m_{2} v_{f2}

1.3m_{1} v_{i1}   =m_{2} v_{f2}

divide both  side by m_{2}

v_{f2}=\frac{1.3m_{1} v_{i1}}{m_{2} }

Now substitute

v_{f2} =\frac{1.3*0.12*v_{i1}}{2.4}\\v_{f2}    =\frac{0.156v_{i1} }{2.4} \\v_{f2} =0.065v_{i1}

v_{f2} =6.5%v_{i1}

<em />

6 0
3 years ago
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Maksim231197 [3]

Answer:

For any collision occurring in an isolated system, momentum is conserved. The total amount of momentum of the collection of objects in the system is the same before the collision as after the collision.

Explanation:

Hope this helps

5 0
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1. What function does the skull serve for the skeleton?
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1.c
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8 0
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alexdok [17]

Answer:

Explanation:

Frequency refers to the number of occurrences of a periodic event per time and is measured in cycles/second. In this case, there is 1 cycle per 2 seconds. So the frequency is 1 cycles/2 s = 0.5 Hz.

4 0
3 years ago
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