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3 years ago

6

In the 1950s, while demand for lumber was high, the Great Cloudy Mountains were wiped clean of trees. Today, an effort to grow b

ack the trees is being made. This sort of effort is known as

1 answer:

leva [86]3 years ago

6 0

I think the answer is Reforestation

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A 0.2 kg baseball is pitched with a velocity of 40 m/s and is then batted to the pitcher with a velocity of 60 m/s. What is the

sergey [27]

Answer:

The magnitude of change in the ball's momentum is 4 kgm/s

Explanation:

Given;

mass of the ball, m = 0.2 kg

initial velocity of the ball, u = 40 m/s

final velocity experienced by the ball, v = 60 m/s

Therefore, the change in momentum of the ball is given as final momentum minus initial mometum;

ΔP = mv - mu

ΔP = m(v-u)

ΔP = 0.2 (60 - 40)

ΔP = 4 kgm/s

Therefore, the magnitude of change in the ball's momentum is 4 kgm/s

3 0

3 years ago

Magma that cools and crystallizes on Earth's surface forms

Nostrana [21]

The correct answer is:

D. Extrusive rocks.

The explanation:

when extrusive igneous rocks form when magma reaches the Earth's surface a volcano and cools quickly. Most extrusive (volcanic) rocks have small crystals. Examples include basalt, rhyolite, andesite, and obsidian.

6 0

4 years ago

Read 2 more answers

Quia<br> Active<br> 16:05:5<br> A plant root is an example of

pogonyaev

Answer:A plant root is an example of an organ

Explanation:The main function of the root is to collect nutrients and water from the soil.

7 0

3 years ago

Read 2 more answers

Assume you push a 20 kg child in a little red wagon with a force of 100 N. However, the dirt and rocks below the wheels

GenaCL600 [577]

Answer:

a

Explanation:

4 0

3 years ago

A hydraulic press has one piston of diameter 4.0 cm and the other piston of diameter 8.0 cm. What force must be applied to the s

yan [13]

Answer:

The force is $F_1 = 400.8 \ N$

Explanation:

From the question we are told that

The first diameter is $d_1 = 4.0 \ cm = 0.04 \ m$

The second diameter is $d_2 = 8.0 \ cm = 0.08 \ m$

Generally the first area is

$A_1 = \pi * \frac{d^2_1 }{4}$

=> $A_1 = 3.142 * \frac{0.04^2}{4}$

=> $A_1 = 0.00126 \ m^2$

The second area is

$A_2 = \pi * \frac{d^2_2 }{4}$

$A_2 = 3.142 * \frac{0.08^2}{4}$

$A_2 = 0.00503 \ m^2$

For a hydraulic press the pressure at both end must be equal .

Generally pressure is mathematically represented as

$P = \frac{F}{A}$

=>

$\frac{F_1}{A_1 } = \frac{F_2}{A_2 }$

=> $F_1 = \frac{1600}{0.00503} * 0.00126$

=> $F_1 = 400.8 \ N$

8 0

3 years ago