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maxonik [38]
3 years ago
11

An initially stationary object experiences an acceleration of 6 m/s2 for a time of 15 s. How far will it travel during that time

?
Physics
1 answer:
Arisa [49]3 years ago
4 0

Explanation:

Distance = (intial speed)X(Time) + 1/2(acceleration)X(Time) [Third equation of motion]

As initial speed is zero, therefore;

Distance = 1/2(acceleration)X(Time)

              = 1/2 (6 X 15)

              = 1/2 (90)

              = 45 meters

Hence, the object traveled 45 meters.

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NARA [144]
1.5 m/s is the velocity. 9.3 m is the length of aisle, over which Distance will be covered. Time is demanded in which the child will move the cart over the aisle with 1.5 m/s. v=S/t and, t=S/v Put values, t=9.3/1.5=6.2 s
7 0
3 years ago
Soil formation involves both
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3 years ago
a bus is moving at 22m/s [E] for 12s. Then the bus driver slows down at 1.2m/s2 [W] until the bus stops. Determine the total dis
KatRina [158]
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d = vt = (22 m/s)(12 s) = 264 m

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a = (v - v₀)/t
d = v₀t + 0.5at²

Because the object slows down, the acceleration is negative. So,
-1.2 m/s² = (0 m/s - 22 m/s)/t
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d = (22 m/s)(18.33 s) + 0.5(-1.2 m/s²)(18.33 s)²
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Thus,
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3 years ago
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NISA [10]

Answer:

the Arrow X shows the direction of amplitude

Explanation:

As the amplitude is the maximum displacement of a wave from the mean position

8 0
2 years ago
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maxonik [38]

probabilityAnswer:

2/27

Explanation:

The elk can not be eaten so we remove that from the probablity

so we have x/18

songbird = 4/18

mice = 6/18

4/18*6/18 = 2/27

5 0
2 years ago
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