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3 years ago

Which is something that a vacuum tube cannot do?

Physics

2 answers:

Oxana [17]3 years ago

8 0

D) concert electrical energy into thermal energy

Butoxors [25]3 years ago

4 0

Answer:

Explanation:

A vacuum tube is a glass tube that creates the conditions of a vacuum to allow for electric current to pass through it.

Originally, vacuum tubes were used in electronics to amplify electric signals, however, today they have been replaced by more efficient systems, such as transistors.

A vacuum tube can change alternating current into direct current, it can turn a current on or off, and as stated above, it can increase the signal strength. However, it cannot change electrical energy into thermal energy, and that is why the answer is D.

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A volleyball player’s hand applies a 39 N force while in contact with a volleyball for 2 seconds. What is the impulse on the bal

nikklg [1K]

Given:
F = 39 N, the force applied
t = 2 s, the time interval in which the force is applied.

By definition, the impulse is
$I = \int_{0}^{2} F(t) dt = \int _{0}^{2} 39dt = 39*2=78 \, N-s$

Answer: 78 N-s

3 0

3 years ago

Read 2 more answers

Consider the data table charting the speed of a toy car moving across the floor. The line graph representing this data would BES

MrMuchimi

Answer:

The answer is D) diagonal line with varying slope, from 3 to 5 on USATestprep

Explanation:

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3 years ago

How is a mixture different from a compound

aksik [14]

Answer:

Compounds are two or more elements chemically combined in definite proportions by weight.

Mixtures are two or more substances not chemically combined.

Explanation:

Hope this helped Mark BRAINLIEST!!!

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3 years ago

A go-kart accelerates at a rate

stira [4]

Answer:

if it is at a speed of 12.5 m / s it would take 2 minutes

Explanation:

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4 years ago

A Carnot engine operates between temperature levels of 600 K and 300 K. It drives a Carnot refrigerator, which provides cooling

KATRIN_1 [288]

Explanation:

Formula for maximum efficiency of a Carnot refrigerator is as follows.

$\frac{W}{Q_{H_{1}}} = \frac{T_{H_{1}} - T_{C_{1}}}{T_{H_{1}}}$ ..... (1)

And, formula for maximum efficiency of Carnot refrigerator is as follows.

$\frac{W}{Q_{C_{2}}} = \frac{T_{H_{2}} - T_{C_{2}}}{T_{C_{2}}}$ ...... (2)

Now, equating both equations (1) and (2) as follows.

$Q_{C_{2}} \frac{T_{H_{2}} - T_{C_{2}}}{T_{C_{2}}}$ = $Q_{H_{1}} \frac{T_{H_{1}} - T_{C_{1}}}{T_{H_{1}}}$

$\gamma = \frac{Q_{C_{2}}}{Q_{H_{1}}}$

= $\frac{T_{C_{2}}}{T_{H_{1}}} (\frac{T_{H_{1}} - T_{C_{1}}}{T_{H_{2}} - T_{C_{2}}})$

= $\frac{250}{600} (\frac{(600 - 300)K}{300 K - 250 K})$

= 2.5

Thus, we can conclude that the ratio of heat extracted by the refrigerator ("cooling load") to the heat delivered to the engine ("heating load") is 2.5.

4 0

3 years ago