Answer:
Rate of change of area will be 
Explanation:
We have given rate of change of radius 
Radius of the circular plate r = 52 cm
Area is given by 
So 
Puting the value of r and 
So rate of change of area will be
<span>The initial velocity of the bike was 1.67 (vf)m/s. This is found by evaluating 7.5/4.5 which yields the velocity per unit of time which is equivalent to initial velocity.</span>
The value that should be reported for the total mass of three samples of iron will be 0.143 Kg or 143 g
<h3>
What is Mass and Weight ?</h3>
Mass is the quantity of matter. While weight is a gravitational pull on an object. Mass is measured in Kg while weight is measured in Newton.
What value should be reported for the total mass of three samples of iron weighing 117.0 g, 19.43 g, and 6.1043 g?
The total mass will be the sum of the three masses.
The total mass = 117 + 19.43 + 6.1043
The total mass = 142.5343 g
Convert gram to kilogram by dividing the answer by 1000
The total mass = 142.5343/1000
The total mass = 0.1425343 Kg
Therefore, the value that should be reported for the total mass of three samples of iron will be 0.143 Kg or 143 g approximately
Learn more about Mass and Weight here: brainly.com/question/1384116
#SPJ1
Answer:
The velocity of the man is 0.144 m/s
Explanation:
This is a case of conservation of momentum.
The momentum of the moving ball before it was caught must equal the momentum of the man and the ball after he catches the ball.
Mass of ball = 0.65 kg
Mass of the man = 54 kg
Velocity of the ball = 12.1 m/s
Before collision, momentum of the ball = mass x velocity
= 0.65 x 12.1 = 7.865 kg-m/s
After collision the momentum of the man and ball system is
(0.65 + 54)Vf = 54.65Vf
Where Vf is their final common velocity.
Equating the initial and final momentum,
7.865 = 54.65Vf
Vf = 7.865/54.65 = 0.144 m/s
K.E.= 1/2 x MV^2 = 1/2 x 40(kg) x (25x25) =12500J
