Answer:
Newton's First Law of Motion
Explanation:
Newton’s first law of motion is when an object can’t move or change their speed without some type of force. Inertia is included since is caused by unbalanced force.
Answer:
Solute - The solute is the substance that is being dissolved by another substance. In the example above, the salt is the solute. Solvent - The solvent is the substance that dissolves the other substance.
Explanation:
2-Chlorobutane, 2-Bromo-3-methylbutane are chiral .
chiral condition - a compound is said to be chiral if it is surrounded by 4 different groups
I,IV are chiral
II,III are achiral
Molecular types with non-superposable mirror images are known as chiral molecules. The existence of an asymmetric carbon atom in a molecule is the characteristic that most frequently contributes to chirality. When referring to an object that cannot be superposed on its mirror counterpart, the adjective "chiral" is generally employed.
A corkscrew, golf clubs, scissors, and other chiral items all have a "handedness." Thus, one can get scissors and golf clubs that are designed for either hand. Gloves and shoes are also sold in pairs, a right and a left.
learn more about chiral molecules here:
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Whats your question? id love to help but I’m not sure I understand
Answer:
see explanations
Explanation:
4NH₃(g) + 5O₂(g) => 4NO(g) + 6H₂O(g)
Ci(NH₃) = 3.5mole/4L = 0.875M
Cf(NH₃) = 1.6mole/4L = 0.400M
Rate-1 => Δ[NH₃]/Δt = |(0.400M - 0.875M)/3min| = 0.158M/s
Rate-2 => 6(Δ[NH₃]/Δt) = 4(Δ[H₂O]/Δt) => 6/4(0.158M/s) = 0.237M/s
Rate-3 => 5(Δ[NH₃]/Δt) = 4(Δ[O₂]/Δt) => 5/4(0.158M/s) = 0.237M/s
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NOTE: When setting up comparative rate expressions for a given reaction, set the rates expressions as equal then swap coefficient values. Then solve for rate of interest and substitute givens.
example: for NH₃ and H₂O
- set rates expressions equal => Δ[NH₃]/Δt = Δ[H₂O]/Δt
- then swap and insert coefficients from given rxn ...
- solve for rate of interest ...
4NH₃(g) + 5O₂(g) => 4NO(g) + 6H₂O(g)
=> 6(Δ[NH₃]/Δt) = 4(Δ[H₂O]/Δt)
=> Δ[H₂O]/Δt = 6/4(Δ[NH₃]/Δt) = 6/4(0.237M/s) = 0.237M/s