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GalinKa [24]
3 years ago
13

C3h8 + 5 o2 --> 3 co2 + 4 h2o this is an example of a _______________.

Chemistry
2 answers:
drek231 [11]3 years ago
5 0
<span><u><em>Answer:</em></u>
combustion reaction

<u><em>Explanation:</em></u>
In chemistry, a <u>combustion reaction</u> is defined as a reaction between an oxidant and any compound that leads to the production of another compound along with a huge amount of heat.

<u>Now, let's check the reaction given:</u>
C</span>₃H₈<span> + 5 O</span>₂<span> --> 3 CO</span>₂<span> + 4 H</span>₂O<span>
<u>The oxidant</u> is oxygen gas
<u>The compound reacting</u> is propane
<u>The compound produced</u> is carbon dioxide along with water vapor and heat

Therefore, the given reaction is a combustion reaction

Hope this helps :)</span>
Contact [7]3 years ago
4 0

Answer: C_{3}H_{8} + 5O_{2} \rightarrow 3CO_{2} + 4H_{2}O this is an example of a combustion reaction.

Explanation:

A reaction in which a compound reacts with oxygen and results in the formation of carbon dioxide and water is known as combustion reaction.

For example, C_{3}H_{8} + 5O_{2} \rightarrow 3CO_{2} + 4H_{2}O is a combustion reaction.

Also, it is known that combustion reactions are exothermic in nature because heat is released during these reactions.

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When you boil water on the stove some steam will rise from the pan. Which of these is a true statement right as the water begins
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B. The water and steam contain the same amount of energy.

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A researcher selects three regions X, Y, and Z, and records the types of discharge that enter the regions’ rivers.
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Region Z should be monitored more closely to avoid health issues.

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3 0
2 years ago
Find the mass of 3.27 x 10^23 molecules of H2SO4. Use 3 significant digits<br> and put the units.
marta [7]

Answer:

Approximately 53.3\; \rm g.

Explanation:

Lookup Avogadro's Number: N_{\rm A} = 6.02\times 10^{23}\; \rm mol^{-1} (three significant figures.)

Lookup the relative atomic mass of \rm H, \rm S, and \rm O on a modern periodic table:

  • \rm H: 1.008.
  • \rm S: 32.06.
  • \rm O: 15.999.

(For example, the relative atomic mass of \rm H is 1.008 means that the mass of one mole of \rm H\! atoms would be approximately 1.008\! grams on average.)

The question counted the number of \rm H_2SO_4 molecules without using any unit. Avogadro's Number N_{\rm A} helps convert the unit of that count to moles.

Each mole of \rm H_2SO_4 molecules includes exactly (1\; {\rm mol} \times N_\text{A}) \approx 6.02\times 10^{23} of these \rm H_2SO_4 \! molecules.

3.27 \times 10^{23} \rm H_2SO_4 molecules would correspond to \displaystyle n = \frac{N}{N_{\rm A}} \approx \frac{3.27 \times 10^{23}}{6.02 \times 10^{23}\; \rm mol^{-1}} \approx 0.541389\; \rm mol of such molecules.

(Keep more significant figures than required during intermediary steps.)

The formula mass of \rm H_2SO_4 gives the mass of each mole of \rm H_2SO_4\! molecules. The value of the formula mass could be calculated using the relative atomic mass of each element:

\begin{aligned}& M({\rm H_2SO_4}) \\ &= (2 \times 1.008 + 32.06 + 4 \times 15.999)\; \rm g \cdot mol^{-1} \\ &= 98.702\; \rm g \cdot mol^{-1}\end{aligned}.

Calculate the mass of approximately 0.541389\; \rm mol of \rm H_2SO_4:

\begin{aligned}m &= n \cdot M \\ &\approx 0.541389\; \rm mol \times 98.702\; \rm g \cdot mol^{-1}\\ &\approx 53.3\; \rm g\end{aligned}.

(Rounded to three significant figures.)

6 0
3 years ago
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