Answer:
The answer to your question is V2 = 29.6 l
Explanation:
Data
Pressure 1 = P1 = 12 atm
Volume 1 = V1 = 23 l
Temperature 1 = T1 = 200 °K
Pressure 2 = 14 atm
Volume 2 = V2 = =
Temperature 2 = T2 = 300°K
Process
1.- To solve this problem use the Combine gas law.
P1V1/T1 = P2V2/T2
-Solve for V2
V2 = P1V1T2 / T1P2
2.- Substitution
V2 = (12)(23)(300) / (200)(14)
3.- Simplification
V2 = 82800 / 2800
4.- Result
V2 = 29.6 l
P=0.0902 g/l
v=22.4 l/mol (stp)
M=vp
M=22.4 l/mol * 0.0902 g/l=2.020 g/mol
M=2.020 g/mol
Answer:
Sink
Explanation:
For a substance to float in water, it must be less dense than water. The density of water is 1 g/cm^3. To find the density of the substance, we can do mass/volume, which in this case is 25g/7cm^3. We see that
, so the substance would sink.
Answer : The mass of
occupy 30.3 L under the same conditions will be, 24.9 grams.
Explanation :
First we have to calculate the moles of 

Now we have to calculate the moles of
in 30.3 L by using Avogadro's law.
Avogadro's law : It is defined as the volume of gas is directly proportional to the number of moles of gas at constant pressure and temperature.

or,

where,
= initial volume of gas = 6.21 L
= final volume of gas = 30.3 L
= initial moles of gas = 0.16 mol
= final temperature of gas = ?
Now put all the given values in the above equation, we get:


Now we have to calculate the mass of 

Molar mass of
= 32 g/mol

Therefore, the mass of
occupy 30.3 L under the same conditions will be, 24.9 grams.