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Norma-Jean [14]
3 years ago
5

A new grill has a mass of 30.0 kg. you put 1.5 kg of charcoal in the grill. you burn all the charcoal and the grill has a mass o

f 30.0 kg. what is the mass in kg of the gases given off? (assume that the charcoal is pure carbon solid and that it burns completely in oxygen).
Chemistry
1 answer:
atroni [7]3 years ago
7 0

The reaction for burning of charcoal or complete combustion is as follows:

C(s)+O_{2}(g)\rightarrow CO_{2}(g)

From the above balanced reaction, 1 mole of carbon releases 1 mole of CO_{2} gas.

Converting mass of charcoal into moles as follows:

n=\frac{m}{M}

Molar mass of pure carbon is 12 g/mol thus,

n=\frac{1.5\times 10^{3} g}{12 g/mol}=125mol

The same moles of CO_{2} is released. Converting these moles into mass as follows:

m=n×M

Molar mass of CO_{2} is 44 g/mol thus,

m=125mol\times 44 g/mol=5.5\times 10^{3}g

Converting mass into kg,

1g=10^{-3}kg

Thus, total mass of gas released is 5.5 kg.

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Answer:

The nitrogens are both sp3 hybridized. Their  bonds are formed by sp overlaps. The carbon and oxygen are sp2 hybridized. The double bond with oxygen is produced by a sp2 overlap to form the sigma component and a probital overlap to form the pi component. The bonds with hydrogen are formed by sp2 overlaps.

Explanation:

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3 years ago
Pure research becomes ___ when scientists develop a hypothesis based on the data and try to solve a specific problem
Inessa05 [86]

Answer:

The answer is <u>applied research</u>

Explanation:

Pure research becomes <u>applied research</u> when scientists develop a hypothesis based on the data and try to solve a specific problem.

This is because the pure research try to understand, predict or explain the behavior of different phenomena <em>(the data)</em> while the applied research try to develop new technologies or methods (<em>hypothesis)</em> to take part, intervene and/or create changes on these phenomena and solve a <em>specific problem.</em>

5 0
3 years ago
0. A liquid solution of LiCl in water at 25°C contains 1 mol of LiCl and 7 mol of water. If 1 mol of LiCl⋅3H2O(s) is dissolved i
kupik [55]

Answer:

19.488 kJ

Explanation:

The overall reaction mechanism shows the reaction between LiCl and H₂O

LiCl.3H_2O ------> Li +\frac{1}{2} Cl_2+3H_2+\frac{3}{2} O_2     -------- (1)

2Li+Cl_2+10H_2O ----->LiCl.10H_2O              -------- (2)

3H_2+\frac{3}{2}O_2 -----> 3H_2O                                     --------- (3)

LiCl.7H_2O ------>  Li + \frac{1}{2} Cl_2+7H_20             ---------- (4)

The overall reaction =

LiCl.7H_2O +LiCl.3H_2O ------>  2LiCl.10H_2O

The heat effects of the above reactions from 1-4 respectively are in the order ; 11311.34 kJ, -857.49 kJ, -873.61 kJ and 439.288kJ respectively

The overall enthalpy change is:

\delta H = \delta H _{LiCl.3H_2O}+\delta H_{3H_2O}  + \delta  H_{2(LiCl.5H_2O)} + \delta  H _{liCl.7H_2O}

\delta H =Q at constant pressure;

Thus; Q = 1311.3 (kJ)  857.49 (kJ) -873.61 (kJ) + 439.288 (kJ)

Q = 19.488 kJ

Thus, the heat effect = 19.488 kJ after the addition of  1 mol of LiCl⋅3H2O(s)

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ANEK [815]

Answer:

the right side of the arrow.

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