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andriy [413]
3 years ago
7

The theoretical yield of Cl2 from certain starting amounts of MnO2 and HCl was calculated as 60.25 g and 65.02 g, respectively.

If the percentage yield of Cl2 is 72%, what is its actual yield?
Chemistry
1 answer:
hoa [83]3 years ago
8 0

The actual yield is 43 g Cl₂.

The <em>limiting reactant was MnO₂</em> because it gave the smaller mass of Cl₂.

∴ The <em>theoretical yield</em> is 60.25 g Cl₂.

% yield = actual yield/theoretical yield × 100 %

Actual yield = theoretical yield × (% yield/100 %) = 60.25 g × (72 %/100%) = 43 g

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