<u>Answer:</u> The percent yield of the reaction is 32.34 %
<u>Explanation:</u>
To calculate the number of moles, we use the equation:
.....(1)
Given mass of benzoic acid = 3.6 g
Molar mass of benzoic acid = 122.12 g/mol
Putting values in equation 1, we get:
![\text{Moles of benzoic acid}=\frac{3.6g}{122.12g/mol}=0.0295mol](https://tex.z-dn.net/?f=%5Ctext%7BMoles%20of%20benzoic%20acid%7D%3D%5Cfrac%7B3.6g%7D%7B122.12g%2Fmol%7D%3D0.0295mol)
The chemical equation for the reaction of benzoic acid and methanol is:
![\text{Benzoic acid + methanol}\rightarrow \text{methyl benzoate}](https://tex.z-dn.net/?f=%5Ctext%7BBenzoic%20acid%20%2B%20methanol%7D%5Crightarrow%20%5Ctext%7Bmethyl%20benzoate%7D)
By Stoichiometry of the reaction
1 mole of benzoic acid produces 1 mole of methyl benzoate
So, 0.0295 moles of benzoic acid will produce =
moles of methyl benzoate
- Now, calculating the mass of methyl benzoate from equation 1, we get:
Molar mass of methyl benzoate = 136.15 g/mol
Moles of methyl benzoate = 0.0295 moles
Putting values in equation 1, we get:
![0.0295mol=\frac{\text{Mass of methyl benzoate}}{136.15g/mol}\\\\\text{Mass of methyl benzoate}=(0.0295mol\times 136.15g/mol)=4.02g](https://tex.z-dn.net/?f=0.0295mol%3D%5Cfrac%7B%5Ctext%7BMass%20of%20methyl%20benzoate%7D%7D%7B136.15g%2Fmol%7D%5C%5C%5C%5C%5Ctext%7BMass%20of%20methyl%20benzoate%7D%3D%280.0295mol%5Ctimes%20136.15g%2Fmol%29%3D4.02g)
- To calculate the percentage yield of methyl benzoate, we use the equation:
![\%\text{ yield}=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100](https://tex.z-dn.net/?f=%5C%25%5Ctext%7B%20yield%7D%3D%5Cfrac%7B%5Ctext%7BExperimental%20yield%7D%7D%7B%5Ctext%7BTheoretical%20yield%7D%7D%5Ctimes%20100)
Experimental yield of methyl benzoate = 1.3 g
Theoretical yield of methyl benzoate = 4.02 g
Putting values in above equation, we get:
![\%\text{ yield of methyl benzoate}=\frac{1.3g}{4.02g}\times 100\\\\\% \text{yield of methyl benzoate}=32.34\%](https://tex.z-dn.net/?f=%5C%25%5Ctext%7B%20yield%20of%20methyl%20benzoate%7D%3D%5Cfrac%7B1.3g%7D%7B4.02g%7D%5Ctimes%20100%5C%5C%5C%5C%5C%25%20%5Ctext%7Byield%20of%20methyl%20benzoate%7D%3D32.34%5C%25)
Hence, the percent yield of the reaction is 32.34 %