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3 years ago

Which statement best compares potential and kinetic energy?

Chemistry

1 answer:

VMariaS [17]3 years ago

4 0

Answer:

nombres uno

number 1

Explanation:

it is what it is according to physicodeferigolical

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Help please please help please

Anni [7]

Answer:

I don't fully understand what this is about...

Explanation:

sorry :(

5 0

3 years ago

Read 2 more answers

Which phrase best describes activation energy? (1 point)

iren [92.7K]

Answer: the minimum amount of energy required to break bonds and start a chemical reaction

Explanation: got a 100% on the quick check

8 0

2 years ago

The vapor pressure of water at 65oC is 187.54 mmHg. What is the vapor pressure of a ethylene glycol (CH2(OH)CH2(OH)) solution ma

Pavlova-9 [17]

Answer:

173.83 mmHg is the vapor pressure of a ethylene glycol solution.

Explanation:

Vapor pressure of water at 65 °C= $p_o= 187.54 mmHg$

Vapor pressure of the solution at 65 °C= $p_s$

The relative lowering of vapor pressure of solution in which non volatile solute is dissolved is equal to mole fraction of solute in the solution.

Mass of ethylene glycol = 22.37 g

Mass of water in a solution = 82.21 g

Moles of water= $n_1=\frac{82.21 g}{18 g/mol}=4.5672 mol$

Moles of ethylene glycol= $n_2=\frac{22.37 g}{62.07 g/mol}=0.3603 mol$

$\frac{p_o-p_s}{p_o}=\frac{n_2}{n_1+n_2}$

$\frac{187.54 mmHg-p_s}{187.54 mmHg}=\frac{0.3603 mol}{0.3603 mol+4.5672 mol}$

$p_s=173.83 mmHg$

173.83 mmHg is the vapor pressure of a ethylene glycol solution.

6 0

3 years ago

Substance X is a compound containing 632mg of manganese and 368mg of oxygen. Substance X is shown

defon

The empirical formula : MnO₂.

<h3>Further explanation</h3>

Given

632mg of manganese(Mn) = 0.632 g

368mg of oxygen(O) = 0.368 g

M Mn = 55

M O = 16

Required

The empirical formula

Solution

You didn't include the pictures, but the steps for finding the empirical formula are generally the same

Find mol(mass : atomic mass)

Mn : 0.632 : 55 = 0.0115

O : 0.368 : 16 =0.023

Divide by the smallest mol(Mn=0.0115)

Mn : O =

$\tt \dfrac{0.0115}{0.0115}\div \dfrac{0.023}{0.0115}=1\div 2$

The empirical formula : MnO₂

8 0

3 years ago

The compound 1-butene is modeled here. What would need to happen for molecules of this compound to transform into polybutene? A.

kompoz [17]

In order to form polymers, we need to chain molecules together. This involves making bonds between them.

Shifting H’s around doesn’t accomplish anything.

Forming more double bonds will have the opposite result, as it would make the molecules more stable and less likely to react with each other.

Adding oxygen to the molecule no longer makes it polybutene. That would likely result in the formation of some sort of ether, as hey would react to form a C-O-C Bond.

The only answer left is A. In order to form polyalkenes, we have to break a double bond so that it’s available to form more covalent bonds.

Hope this helps

4 0

3 years ago