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marshall27 [118]
3 years ago
9

What are the independent and dependant variables in Plate Tectonics Lab Report?

Physics
2 answers:
tresset_1 [31]3 years ago
5 0

Answer:

I don't know the exact answer but I think this is it.

The independent variable is the variable the experimenter changes or controls and is assumed to have a direct effect on the dependent variable. The dependent variable is the variable being tested and measured in an experiment, and is 'dependent' on the independent variable.

mario62 [17]3 years ago
5 0
Independent is what you’re controlling the dependent is what ur making the lab on like let’s say water two plants but adding different amounts of water the dependent is the plant bc it doesn’t change but the amount of water is what you control so that would be your independent hope that made sense :)
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A 5.00-A current runs through a 12-gauge copper wire (diameter 2.05 mm) and through a light bulb. Copper has 8.5 * 1028 free ele
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Answer:

a)n= 3.125 x 10^{19 electrons.

b)J= 1.515 x 10^{6 A/m²

c)V_{d =1.114 x 10^{4m/s

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Explanation:

Current 'I' = 5A =>5C/s

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radius 'r' = d/2 => 1.025 x 10^{-3 m

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I= Q/t

Q= I x t => 5 x 1

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As we know that: Q= ne

where e is the charge of electron i.e 1.6 x 10^{-19C

n= Q/e => 5/ 1.6 x 10^{-19

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b)  the current density 'J' in the wire is given by

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J= 5 / (3.14 x (1.025x 10^{-3)²)

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V_{d =1.114 x 10^{4m/s

d) According to these equations,

J= I/A

V_{d = \frac{J}{n|q|} =\frac{I}{nA|q|}

If you were to use wire of twice the diameter, the current density and drift speed will change

Increase in the diameter increase the cross sectional area and decreases the current density as it has inverse relation.

Also drift velocity will decrease as it is inversely proportional to the area

 

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