Answer:
a. The electric field lines are linear and perpendicular to the plates inside a parallel-plate capacitor, and always from positive plate to the negative plate. If a positive charge is released near the positive plate, then it will follow a linear path towards the negative plate under the influence of electrostatic force, F = Eq, where q is the charge of the particle. The electric field inside a parallel plate capacitor is constant and equal to
This can be calculated by Gauss' Law.
A positive charge always follow the electric field lines when released. Another approach is that the positive plate repels the positive charge and negative plate attracts the positive charge. Therefore, the positive charge follows a path towards the negative charge.
b. The particle moves from the higher potential to the lower potential. The direction of motion is the same as the direction of the force that moves the particle, so the work done on the particle by that force is positive.
Answer:
450.78Hz
Explanation:
The frequency of wave in string is directly proportional to its tension. This is mathematically expressed as
F∝T
F = kT where k is the constant of proportionality
From the formula, k = F/T
F1/T1 = F2/T2 = k
If each violin is perfectly tuned at 440 Hz and under 245 N of tension then F1 = 440Hz, T1 = 245N
To get the frequency if the string A is tighten to 251N of tension,
T2 = 251N, F2 =?
Substituting the given values into the equation above to get F2 we have;
440/245 = F2/251
Cross multiplying
245F2 = 440×251
245F2 = 110,440
F2 = 110,440/245
F2 = 450.78Hz
It is equal to the acceleration of the object.
Answer: Physical is the blank space
Explanation: Your welcome
Answer:
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Explanation: