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2 years ago

Most cars today use an ___ combustion engine ... A. internal B. external

Physics

2 answers:

Sphinxa [80]2 years ago

5 0

Answer:

A. internal

Explanation:

Engine is the name given to the equipment responsible for turning energy into motion of the vehicle in which it is installed. In the case of cars and other vehicles, the engine is called “internal combustion” because it transforms the burning of fuels in its interior in motion.

Regardless of engine type, everyone needs the same elements: air, fuel, and an explosion trigger. In Otto engines, this trigger is provided by the spark plug, which unleashes a spark inside the cylinder and generates the explosion. In diesel engines, such an explosion is generated by the compression of gases within the cylinder and the elevated temperature.

Greeley [361]2 years ago

4 0

A. Internal. Most cars use that type of set up because it's more efficient, you can find more about it on this website, https://auto.howstuffworks.com/did-cars-ever-have-external-combustion-engines.htm

~ Ria

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3 years ago

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Kyle has a mass of 54kg and is moving at 3 m/s what is his kinetic energy

Mars2501 [29]

Answer:

243J

Explanation:

K.E = 1/2 x 54 x 3^2

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3 years ago

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3 years ago

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How many grams of CO2 are in 10 mol of the compound?

Zepler [3.9K]

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3 years ago

A 5-kg ball collides inelastically head-on with a 10-kg ball, which is initially stationary. Which of the following statements i

NARA [144]

Answer:

The magnitude of the change of velocity the 5-kg ball experiences is less than that of the 10-kg ball.

Explanation:

In inelastic collision, the total momentum is always conserved after collision but the kinetic energy is reduced.

Momentum is Mass X velocity.

5 kg ball is in motion, while 10 kg ball is stationary; that is zero velocity.

The momentum of 10 kg ball before collision is zero while the momentum of 5 kg ball before collision is more than zero. Therefore, the magnitude of change in momentum will not be equal.

Next possible options are in kinetic Energy

Initial Kinetic energy = $\frac{1}{2}mu^2$

Final kinetic energy = $\frac{1}{2}mv^2$

Change in kinetic energy = Final Kinetic Energy - Initial Kinetic Energy

Change in kinetic energy of 5kg ball = $\frac{1}{2}mv^2 -\frac{1}{2}mu^2 = \frac{1}{2}m(v-u)^2$

Since the 5-kg ball has initial velocity (u), the magnitude of the change in velocity will be reduced.

Change in kinetic energy of 10kg ball:

the ball is initially at rest, therefore the initial velocity (u) will be zero (0)

Δ K.E = $\frac{1}{2}mv^2 -\frac{1}{2}mu^2 = \frac{1}{2}m(v-u)^2 = \frac{1}{2}m(v-0)^2 = \frac{1}{2}mv^2$

From the solution above, the magnitude of the change in velocity experienced by 10 kg ball is higher than 5 kg ball.

Hence, The magnitude of the change of velocity the 5-kg ball experiences is less than that of the 10-kg ball

4 0

3 years ago