All categories

3 years ago

Calculate the average orbital speed of Ceres in

1 answer:

8 0

] Ceres is composed of rock and ice and is estimated to comprise approximately one third of the mass of the entire asteroid belt. Ceres is the only object in the asteroid belt known to be rounded by its own gravity (though detailed analysis was required to exclude 4 Vesta). From Earth, the apparent magnitude of Ceres ranges from 6.7 to 9.3, peaking once every 15 to 16 months,[21]hence even at its brightest it is too dim to be seen with the naked eye except under extremely dark skies.

You might be interested in

What kind of waves can cause the most damage on the earth's surface?

Karo-lina-s [1.5K]

Answer:

Surface waves, in contrast to body waves can only move along the surface. They arrive after the main P and S waves and are confined to the outer layers of the Earth. They cause the most surface destruction. Earthquake surface waves are divided into two different categories: Love and Rayleigh.

Explanation:

Hope this helped Mark BRAINLIEST!!!

4 0

2 years ago

Read 2 more answers

Planets in our solar system revolve around the Sun because

vodomira [7]

C. The sun is the most massive object in our solar system.
It also has a stronger gravitational pull.

6 0

2 years ago

Read 2 more answers

A grinding wheel is in the form of a uniform solid disk of radius 7.00 cm and mass 2.00 kg. It starts from rest and accelerates

Veronika [31]

Answer:

Part a)

$t = 1.03 s$

Part b)

$N = 10.3 rev$

Explanation:

Mass of the disc is given as

m = 2.00 kg

radius of the disc is given as

r = 7 cm

so moment of inertia of the disc is given as

$I = \frac{1}{2}mr^2$

$I = \frac{1}{2}(2)(0.07)^2$

$I = 4.9 \times 10^{-3} kg m^2$

Now given that torque on the disc is

$\tau = 0.600 Nm$

so here the angular acceleration is given as

$\alpha = \frac{\tau}{I}$

$\alpha = \frac{0.600}{4.9 \times 10^{-3}}$

$\alpha = 122.45 rad/s^2$

Part a)

if disc start from rest and then achieve final speed as 1200 rpm then

$f = 1200/60 = 20 rev/s$

so final speed is

$\omega = 2\pi(20) = 40\pi rad/s$

now the time taken to reach this speed is given as

$\alpha t = \omega$

$(122.45) t = 40\pi$

$t = 1.03 s$

Part b)

Number of revolution in the same time is given as

$N = \frac{\omega_o + \omega}{4\pi} t$

$N = \frac{40\pi + 0}{4\pi}(1.03) = 10.3 rev$

6 0

2 years ago

What is the mass of an object if a net force of 8.0 N causes it to accelerate at 1.1 m/s2?

nataly862011 [7]

Using , F= ma .
where F is netforce , m is mass and a is acceleration produced .
=> m=F/a.
m= 8/1.1 = 7.27 Kg.

4 0

3 years ago

A net force F acts on a mass m and produces an acceleration a. What acceleration results if a net force 4F acts on a mass 6m?

stepladder [879]

Answer: The acceleration results if a net force of 4F acts on a mass of 6m is 2/3a.

Explanation:

Force exerted on an object can be defined as a pull or a push on an object which leads to it's displacement. Force is taken to be a vector quantity because it has both magnitude and direction. The formula which can be used to determine force exerted on an object in physics is:

F= mass( kg) × acceleration( m/ s²)

Acceleration is defined as the rate at which the velocity of an object changes. From the formula of force given above it can be determined by making it the subject of formula. Therefore acceleration= Force/ mass.

From the question,

Force= 4F

Mass= 6m

Therefore acceleration= F/m

= 4/6

Acceleration= 2/3a

5 0

2 years ago