Answer:
SI unit of density - Kilogram per cubic metre (Kg/m³)
CGS unit of density - gram per cubic centimetre (g/cm³)
Answer:
(a) The magnitude of the bird watcher's displacement is: 1.739 Km and (b) Average Velocity is: 0.863 Km/h.
Explanation:
To know the magnited of the bird watcher's displacement, we need to use cartesian coordinates. The distance that the bird watcher walked is the vector addition of all movement from the start point. So East = 1.4 - 3.26*Cos(78.6) = 0.756 Km and North = -1.63 + 3.26*Sen (78.6) = 1.566 Km when we have got result of both components axles, we use the pythagorean theorem to get the displacement that the bird watcher walked; R^{2}=x^{2}+y^{2} =\sqrt{0.756^{2}+(1.566)^{2}}=1.739(Km). Then we are going to calculate average velocity as: where delta_x is the displacement traveled by the bird watcher and delta_t is the total time using during the movement, so .
Answer:
The velocity is
Henrietta is at distance from the under the window
Explanation:
From the question we are told that
The speed of Henrietta is
The height of the window from the ground is
Generally the time taken for the lunch to reach the ground assuming it fell directly under the window is
=>
=>
Generally the time taken for the lunch to reach Henrietta is mathematically represented as
Here is the time duration that elapsed after Henrietta has passed below the window the value is given as 4 s
Now
=>
Generally the distance covered by Henrietta before catching her lunch is
=>
=>
Generally the speed with which Bruce threw her lunch is mathematically represented as
I see no multiple choice answer
Answer:
Air resistance
Answer B is correct
Explanation:
The friction that occurs when air pushes against a moving object causing it to negatively accelerate is called as air resistance.
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