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dalvyx [7]
3 years ago
6

a body starts from rest with a uniform acceleration of 2m s-2 find the distance covered by the body in 2s

Physics
1 answer:
Evgen [1.6K]3 years ago
8 0
Finding acceleration= final velocity-initial velocity/ time taken (or A= V-U/T)

Final speed= 2m
Initial speed= 0m
Time taken= 2 seconds

2-0/2 so it’ll be 1m/s

2-0=0
2/2=

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Please Help!!
kotegsom [21]

Answer:

Potential energy of spring = 24 Joules.

Explanation:

Given the following data;

Spring constant = 85N/m

Extension, e = 0.75m

Mass = 25kg

To find the potential energy of a spring

Potential energy of a spring is given by the formula;

P.E = ½ke²

Substituting into the equation, we have

P.E = ½*85*0.75²

P.E = 42.5 * 0.5625

P.E = 23.91 ≈ 24 Joules

P.E = 24 Joules

8 0
3 years ago
a football quarterback throws a football. after it leaves his hand, what forces are acting on the football? choose all that appl
MAVERICK [17]

golekeeper

Explanation:

because they use hand to save keeper

3 0
2 years ago
An undiscovered planet, many lightyears from Earth, has one moon in a periodic orbit. This moon takes 2010 × 103 seconds (about
vazorg [7]

Answer:

Radial acceleration of moon is a_{r} = 2.246\times 10^{-3}\frac{m}{s^{2} }

Explanation:

Given :

Time period T = 1.987 \times 10^{6} sec

Distance from center of moon to planet r = 225 \times 10^{6} m

From the equation of radial acceleration,

  a_{r} = r\omega ^{2}

Where \omega = 2\pi f = \frac{2\pi }{T}

So   \omega = 3.16 \times 10^{-6} \frac{rad}{s}

Now moon's radial acceleration,

 a_{r} = 225 \times 10^{6} \times (3.16 \times 10^{-6} )^{2}

 a_{r} = 2246.76 \times 10^{-6}

 a_{r} = 2.246\times 10^{-3} \frac{m}{s^{2} }

7 0
3 years ago
The football team is selling mulch as a fundraiser. Which two options are
satela [25.4K]
Noise does not affect the digital signal making it more reliable
3 0
3 years ago
Read 2 more answers
Periodic waves spread out over the surface of a lake where two women, Jenny and Melissa, are fishing in separate boats 46 meters
Tatiana [17]

Answer:

The wavelength of the water is \lambda = 10.22 m

Explanation:

From the question awe are told that

                The distance between the two boats are 46 m

   Now we are told that a the time the Jenny's boat is at a crest,Melissa's boat is at its lowest point, and there are 4 additional crests between them which can be mathematically represented as

                         Number of wavelength = 4 + 0.5(this accounts for the difference in position crest and lowest point)

                                                              = 4.5

Now the wavelength of the water is \lambda = \frac{Distance }{Number \ of \ division }

                                                                 = \frac{46}{4.5} =10.22m

8 0
3 years ago
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