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dalvyx [7]
3 years ago
6

a body starts from rest with a uniform acceleration of 2m s-2 find the distance covered by the body in 2s

Physics
1 answer:
Evgen [1.6K]3 years ago
8 0
Finding acceleration= final velocity-initial velocity/ time taken (or A= V-U/T)

Final speed= 2m
Initial speed= 0m
Time taken= 2 seconds

2-0/2 so it’ll be 1m/s

2-0=0
2/2=

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A flywheel with a radius of 0.300 m starts from rest and accelerates with a constant angular acceleration of 0.600 rad/s2. Compu
boyakko [2]

Answer:

0.42 m/s²

Explanation:

r = radius of the flywheel = 0.300 m

w₀ = initial angular speed = 0 rad/s

w = final angular speed = ?

θ = angular displacement = 60 deg = 1.05 rad

α = angular acceleration = 0.6 rad/s²

Using the equation

w² = w₀² + 2 α θ

w² = 0² + 2 (0.6) (1.05)

w = 1.12 rad/s

Tangential acceleration is given as

a_{t} = r α = (0.300) (0.6) = 0.18 m/s²

Radial acceleration is given as

a_{r} = r w² = (0.300) (1.12)² = 0.38 m/s²

Magnitude of resultant acceleration is given as

a = \sqrt{a_{t}^{2} + a_{r}^{2}}

a = \sqrt{0.18^{2} + 0.38^{2}}

a = 0.42 m/s²

8 0
3 years ago
A 5.0 kg box slides down a 4.0 m long ramp that makes a 25 angle with the ground. If the coefficient of kinetic friction is 0.65
Sedaia [141]

The thermal energy was produced is 116J

<h3>What is the thermal energy produced?</h3>

Now we know that the frictional force produces the energy that is lost as heat as the body slides down the incline. The magnitude of the frictional force is obtained from;

Ff= μmgcosθ

Ff =  0.65 *  5.0 kg * 9.8 m/s^2 * cos 25

Ff = 29 N

Hence, the thermal energy is;

29 N * 4.0 m = 116J

Learn more about frictional force:brainly.com/question/1714663

#SPJ1

4 0
2 years ago
Does the area of contact effect the frictional force . explain?​
OlgaM077 [116]

Answer:

The force due to friction is generally independent of the contact area between the two surfaces. This means that even if you have two heavy objects of the same mass, where one is half as long and twice as high as the other one, they still experience the same frictional force when you drag them over the ground.

Plz mark 5 star, thanks, and brainliest

3 0
3 years ago
Axis Powers used the Anti-Comintern Pact to hide their aggressive intentions with a false pledge to stop the spread of communism
lesantik [10]
What is the question here? if it is true or false?

5 0
3 years ago
Read 2 more answers
HW 5.2.A 5.00-kg chunk of ice is sliding at 12.0 m/s on the floor of an ice-covered valley whenit collides with and sticks to an
Allisa [31]

The concept used to solve this problem is the conservation of momentum and the conservation of energy.

For conservation of the moment we have the definition:

m_1v_1 = (m_1+m_2)v_f

Where,

m = Mass

v_1 = Initial velocity for object 1

v_f = Final velocity

Replacing the values we have to,

m_1v_1 = (m_1+m_2)v_f

5*12=(5+5)v_f

v_f = 6m/s

By conservation of energy we know that the potential energy is equal to the kinetic energy then

mgh = \frac{1}{2} m(v_f^2-v_i^2)

gh = \frac{1}{2} v_f^2

h = \frac{1}{2} g*v_f^2

h = \frac{1}{2} (9.8)(6)^2

h = 1.837m

Therefore after the collision the height when the combined chinks will go is 1.837m

3 0
4 years ago
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