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Rasek [7]
4 years ago
6

Which of these is an example of physical change?

Physics
2 answers:
My name is Ann [436]4 years ago
8 0
That will be A melting a substance that's because the rest are examples of chemical changes and also its the same thing but in a different form.
aleksandrvk [35]4 years ago
7 0

Answer:

Melting a substance

Explanation:

Melting a substance is a physical change. It is a physical change because the process is irreversible that is the product after the substance is melted can be converted back to its original state.

Taking ice as an example, ice being a solid matter can be melted by applying heat. This melted ice will change to water. The water which is the product formed can be freezed to change it back to its initial state which is ice. Hence melting is a physical change.

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A 1,000 kg car is driving on a 15 m high bridge at 5 m/s. What is the kinetic energy of the car?
yanalaym [24]

Answer:

KE=12,500J

Explanation:

The formula for kinetic energy is:

KE = \frac{1}{2}mv^2

We can plug in the given values into the equation:

KE = \frac{1}{2}*1000kg*(5m/s)^2

KE = 500kg*25m^2/s^2

KE=12,500J

7 0
3 years ago
a wave in a rope is traveling at 6 m/s and at a frequency of 2 Hz. what is the wavelength of the wave producced
Tems11 [23]

Answer:

3

Explanation:

4 0
3 years ago
Two cannonballs are dropped from a second-floor physics lab at height h above the ground. Ball B has four times the mass of ball
denpristay [2]

Answer:

1:4

Explanation:

The formula for calculating kinetic energy is:

KE=\dfrac{1}{2}mv^2

If the mass is multiplied by 4, then, the kinetic energy must be increased by 4 as well. Since they will be travelling at the same speed when they are at the same point, the relation between KA and KB must be 1:4 or 1/4. Hope this helps!

3 0
3 years ago
9. What is the equivalent resistance of the circuit shown in the figure below?
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4 0
3 years ago
3 A 100 g steel ball falls from a height of 1.8 m on to a metal plate and rebounds to a height of 1.25 m.​
BigorU [14]

Given values:

Mass of the steel ball, m = 100 g = 0.1 kg

Height of the steel ball, h1 = 1.8 m

Rebound height, h2 = 1.25 m

a.  PE= mgh

0.1 x 9.8 x 1.8 =

1.764 Joules

b. KE = PE ->

1.764 Joules

c. KE= 1/2 mv square

so v = square root 2ke/m

square root 2 x 1.764/ 0.1

= 5.93 m/s

d. KE=PE=mgh square

0.1 x 9.8 x 1.21 =

1.186 joules

velocity of rebond is square root 2x 1.186/ 0.1 = 4.87 m/s

6 0
3 years ago
Read 2 more answers
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