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2 years ago

Reciprocal liking is adaptive because it lowers the risk of relationship rejection.

2 answers:

6 0

I believe that the statement above is TRUE. I can say that it's true because based on the definition of what reciprocal liking is, this is the probability of having to like someone who also likes them in return. Therefore, if they like each other, this means that there is a low risk of rejection in the relationship.

KatRina [158]2 years ago

3 0

Answer:

True

Explanation:

got it right on edge

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A car sitting at a red light begins to accelerate at 2.0 m/s2 when the light turns green. It continues with this acceleration un

KonstantinChe [14]

Answer:

$d = 820 m$

Explanation:

here we know that car starts from rest and continue to accelerate till it will reach to maximum speed of 20 m/s

so we will have

$v_f - v_i = at$

$20 - 0 = 2t$

$t = 10 s$

so car will accelerate till t = 10 then it will move with uniform speed

so the distance moved by the car till it accelerates is given as

$d = \frac{1}{2}at^2$

$d = \frac{1}{2}(2)(10^2)$

$d_1 = 100 m$

now it will move with uniform speed for next 36 s

so we have

$d_2 = 20(36) = 720 m$

so total distance moved by the car is given as

$d = d_1 + d_2$

$d = 100 + 720$

$d = 820 m$

8 0

2 years ago

An object is thrown off a cliff with a horizontal speed of 10 m/sec. After 3 seconds the object hits the ground. Find the height

Degger [83]

Answer:

223

Explanation:

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4 0

2 years ago

How is work calculated when the force applied is not parallel to the displacement

Leno4ka [110]

Pretty sure it’s Force*Distance*Cos(theta)

7 0

2 years ago

Read 2 more answers

The half-life of the radioactive element beryllium-13 is 5 × 10-10 seconds, and half-life of the radioactive element beryllium-1

telo118 [61]

<h2>Answer: The half-life of beryllium-15 is 400 times greater than the half-life of beryllium-13.</h2>

Explanation:

The half-life $h$ of a radioactive isotope refers to its decay period, which is the average lifetime of an atom before it disintegrates.

In this case, we are given the half life of two elements:

beryllium-13: $h_{B-13}=5(10)^{-10}s=0.0000000005s$

beryllium-15: $h_{B-15}=2(10)^{-7}s=0.0000002s$

As we can see, the half-life of beryllium-15 is greater than the half-life of beryllium-13, but how great?

We can find it out by the following expression:

$h_{B-15}=X.h_{B-13}$

Where $X$ is the amount we want to find:

$X=\frac{h_{B-15}}{h_{B-13}}$

$X=\frac{2(10)^{-7}s}{5(10)^{-10}s}$

Finally:

$X=400$

Therefore:

The half-life of beryllium-15 is <u>400 times greater than</u> the half-life of beryllium-13.

8 0

2 years ago

How much current will pass through a 12.5 ohm resistor when it is connected to ta 115 volt source of electrical potential?

Marrrta [24]

Answer:

9.2 amperes

Explanation:

Ohm's law states that the voltage V across a conductor of resistance R is given by $V = R I$

Here, voltage V is proportional to the current I.

For voltage, unit is volts (V)

For current, unit is amperes (A)

For resistance, unit is Ohms (Ω)

Put R = 12.5 and V = 115 in V=RI

$115=12.5I\\I=\frac{115}{12.5}\\ =9.2\,\,amperes$

8 0

3 years ago