Answer:
The weight of object in alcohol is, W₀ = 9.6 N
Explanation:
Given,
The weight of body in air, Wₐ = 10 N
The weight of the body in water, Wₓ = 9.5 N
The density of the alcohol, ρ = 0.8 g/cm³
                                                 = 800 kg/m³
The weight of body in water = weight of object in air - weight of water displaced
                         9.5 N = 10 N - weight of water displaced
                        Weight of water displaced = 0.5 N
The mass of the displaced water, m = 0.5 / 9.8
                                                             = 0.051 kg
Therefore the volume of the water displaced,
                                               V = m / ρ
                                                   = 0.051 / 1000
                                                    = 5.1 x 10⁻⁵ m³
<em>The volume of water displaced is equal to the volume of alcohol displaced</em>
Therefore, the mass of the alcohol displaced, = V x ρ
                                                                              = 5.1 x 10⁻⁵ x 800
                                                                              = 0.0405 kg
The weight of the alcohol displaced, w = 0.0405 x 9.8
                                                                     = 0.4 N
Therefore,
The weight of body in alcohol = weight of object in air - weight of alcohol displaced
                              W₀ = W - w
                                     = 10 N - 0.4 N
                                      = 9.6 N
Hence, the weight of object in alcohol is, W₀ = 9.6 N