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3 years ago

On a particle level, what happens when thermal conduction occurs within a solid?

Physics

1 answer:

yKpoI14uk [10]3 years ago

7 0

Answer:

Faster particles bump into slower particles ( A )

Explanation:

Thermal conduction in a solid involves the microscopic collision of particles in the solid and this particles are made up of electrons, molecules and atoms. the collisions occur when faster particles collide with slower particles and this happens in a disorganized manner.

when cannot say for sure in what direction each of the particles is moving but there is surely collisions between particles which in turn results to transfer of kinetic and potential energies

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Eva8 [605]

The metalcore is the central component of any metal that is covered by wires. Metalcore is found in the X denoted area.

<h3>What is a solenoid?</h3>

A solenoid is a coil of wire that conducts an electric current. A solenoid is an electromagnet made out of a wire or helical coil.

When an electric current is sent through the coil, it produces a magnetic field. A solenoid is a coil that generates a magnetic field when an electric current passes through it.

When a conductive wire is used to build a loop, a solenoid is formed.

Hence the metalcore is found in the given X area.

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3 years ago

What human practices are destroying the rain forest?

marissa [1.9K]

Deforestation, the chopping off of the trees that can take thousands or even millions of years to grow again<span />

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3 years ago

Find the potential inside and outside a uniformly charged solid sphere whose radius is R and whose total charge is q. Use infini

amid [387]

Answer:

Recall that the electric field outside a uniformly charged solid sphere is exactly the same as if the charge were all at a point in the centre of the sphere:

$E_{outside} =\frac{1}{4\pi(e_{0})}\frac{Q}{r^{2} } r^{'}$

lnside the sphere, the electric field also acts like a point charge, but only for the proportion of the charge further inside than the point r:

$E_{inside} =\frac{1}{4\pi(e_{0})}\frac{Q}{R^{2} } \frac{r}{R} r^{'}$

To find the potential, we integrate the electric field on a path from infinity (where of course, we take the direct path so that we can write the it as a 1 D integral):

$V(r>R)=\int\limits^r_\infty {\frac{1}{4\pi(e_{0)} }\frac{Q}{r^2} } \, dr=\frac{q}{4\pi(e_{0)} } \frac{1}{r} \\V(r$

= $\frac{q}{4\pi e_{0} } [\frac{1}{R} -\frac{r^{2}-R^{2} }{2R^{3} } ]$

∴NOTE: Graph is attached

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4 years ago

How does the digestive system help the muscular system?

Sveta_85 [38]

Answer:

I would say the answer is A... but I'm not so sure ....

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3 years ago

A man on the moon throws a ball vertically upwards and it is noticed that the ball travels 3.0m less in the fifth second of its

sdas [7]

<h2>Acceleration due to gravity in moon is 1.5 m/s²</h2>

Explanation:

We have equation of motion s = ut + 0.5 at²

Here the ball travels 3 m less distance in fifth second compared to third second.

That is

s₃ = s₅ + 3

Now we have

Distance traveled in third second, s₃ = u x 3 - 0.5 x g x 3² - u x 2 - 0.5 x g x 2²

s₃ = u - 2.5 g

Also

Distance traveled in fifth second, s₅ = u x 5 - 0.5 x g x 5² - u x 4 - 0.5 x g x 4²

s₅ = u - 4.5 g

That is

u - 2.5 g = u - 4.5 g + 3

2 g = 3

g = 1.5 m/s²

Acceleration due to gravity in moon = 1.5 m/s²

8 0

3 years ago