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3 years ago

On a particle level, what happens when thermal conduction occurs within a solid?

Physics

1 answer:

yKpoI14uk [10]3 years ago

7 0

Answer:

Faster particles bump into slower particles ( A )

Explanation:

Thermal conduction in a solid involves the microscopic collision of particles in the solid and this particles are made up of electrons, molecules and atoms. the collisions occur when faster particles collide with slower particles and this happens in a disorganized manner.

when cannot say for sure in what direction each of the particles is moving but there is surely collisions between particles which in turn results to transfer of kinetic and potential energies

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A grandfather clock works by swinging a pendulum back and forth with a

allochka39001 [22]

Answer:

For example, a wave with a time period of 2 seconds has a frequency of

1 ÷ 2 = 0.5 Hz.

Explanation:

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3 years ago

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Fiesta28 [93]

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3 years ago

he fan blades on a jet engine make one thousand revolutions in a time of 54.9 ms. What is the angular frequency of the blades?

Gnesinka [82]

So, the angular frequency of the blades approximately <u>36.43π rad/s</u>.

<h3>Introduction</h3>

Hi ! Here I will discuss about the angular frequency or what is also often called the angular velocity because it has the same unit dimensions. <u>Angular frequency occurs, when an object vibrates (either moving harmoniously / oscillating or moving in a circle)</u>. Angular frequency can be roughly interpreted as the magnitude of the change in angle (in units of rad) per unit time. So, based on this understanding, the angular frequency can be calculated using the equation :

$\boxed{\sf{\bold{\omega = \frac{\theta}{t}}}}$

With the following condition :

$\sf{\omega}$ = angular frequency (rad/s)
$\sf{\theta}$ = change of angle value (rad)
t = interval of the time (s)

<h3>Problem Solving</h3>

We know that :

$\sf{\theta}$ = change of angle value = 1,000 revolution = 1,000 × 2π rad = 2,000π rad/s >> Remember 1 rev = 2π rad/s.
t = interval of the time = 54.9 s.

What was asked :

$\sf{\omega}$ = angular frequency = ... rad/s

Step by step :

$\sf{\omega = \frac{\theta}{t}}$

$\sf{\omega = \frac{2,000 \pi}{54.9}}$

$\boxed{\sf{\omega \approx 36.43 \pi \: rad/s}}$

<h3>Conclusion :</h3>

So, the angular frequency of the blades approximately 36.43π rad/s.

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2 years ago

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bearhunter [10]

Answer:

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3 years ago

__ is the apparent in the position of an object when viewed from two locations

Yakvenalex [24]

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Hope this helps :)</span>

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3 years ago