Answer:
same value in R and 2R E = E₀ = σ / 2ε₀
Explanation:
For this exercise we use Gauss's law
Ф = E. dA = 
/ε₀
We define a Gaussian surface with a cylinder with the base being parallel to the load sheet, so the electic field line and the normal line to the base are parallel and the scalar product is reduced to the algebraic product, in the parts the angle is 90º and the dot product is zero
As the sheet has two faces
2E A = q_{int} /ε₀
The charge inside the cylinder is
σ = q_{int} / A
q_{int} = σ A
We substitute
E = σ / 2ε₀
We see that this expression is independent of the distance, so it has the same value in R and 2R
E = E₀ = σ / 2ε₀
Newtons second law --> F = ma
So we have mass which = 12.0
And acceleration = 27.0
So the force = (12)(27)
F = 324 N
Answer:
Let the volume of the cube be V and the fraction of cube outside water be f.
Thus, volume of ice inside water = volume of water displaced =(1−f)V
Under equilibrium,
Weight of ice = Weight of water displaced
⟹Vρ
ice
g=(1−f)Vρ
water
g
⟹(1−f)=
10
9
⟹f=
10
1
Thus, the percentage of volume outside water =10%
<span>circumference of orbit = pi*1/2*1.5e11m = 2.356e11 meters
in 13 weeks, there are 13*7*24*60*60 seconds = 7.862e6 seconds
avg speed = 1/4*2.356e11meters/7.862e6sec = 0.07492e5 = 7.49e3m/sec
the avg velocity is 1.414* radius of the orbit </span>
