Answer:
The given equation tells the relationship between the velocity and the length of skid mark,so simply by putting the given values,we can determine the length of the skid mark.
Given,
v
=
25
miles/ hrs=
25
⋅
(
5280
3600
)
f
t
s
i.e
36.67
f
t
s
f
=
0.5
So,from the equation,we get the length of the skid mark=
d
=
36.67
√
32
⋅
0.5
i.e
12.98
f
tExplanation:
A. Density only depends on the substance. It doesn't matter whether you have a little chip of it or a supertanker full of it ... the density doesn't change.
Answer:
a. 12.57 m/s b. 39.5 m/s² c. Her centripetal force is four times her weight.
Explanation:
a. What is Missy's linear speed on the rotor?
Missy's linear speed v = 2πr/T where r = radius = 4.0 m and T = time it takes to complete one revolution = 2.0 s
So, v = 2πr/T
= 2π(4.0 m)/2.0 s
= 4π m/s
= 12.57 m/s
b. What is Missy's centripetal acceleration on the rotor?
Missy's centripetal acceleration, a = v²/r where v = linear velocity = 12.57 m/s and r = radius = 4.0 m
a = v²/r
= (12.57 m/s)²/4.0 m
= 158.01 m²/s² ÷ 4.0 m
= 39.5 m/s²
c. If her mass is 50-Kg, how is the centripetal force compare to her weight?
Her centripetal force F = ma where m = mass = 50 kg and a = centripetal acceleration = 39.5 m/s².
Her weight W = mg where m = mass = 50 kg and g = acceleration due to gravity = 9.8 m/s².
So, comparing her centripetal force to her weight, we have
F/W = ma/mg
= a/g
= 39.5 m/s² ÷ 9.8 m/s²
= 4.03
≅ 4
So her centripetal force is four times her weight.
Answer:
8m
Explanation:
The magnitude m of a vector (x, y) is given by
m = -------------------------(i)
where;
x and y are the x- and y- components of the vector.
From the question;
m = 10m
x = 6m
Substitute these values into equation (i) as follows;
10 =
Solve for y;
<em>Find the square of both sides</em>
10² = 6² + y²
100 = 36 + y²
y² = 100 - 36
y² = 64
y = √64
y = 8
Therefore, the y-component of the position vector is 8m
If the mass of one of the objects is doubled, then the force of gravity between them is doubled. ... Since gravitational force is inversely proportional to the square of the separation distance between the two interacting objects, more separation distance will result in weaker gravitational forces.