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Sloan [31]
2 years ago
7

Solids, liquids, and gases are very often depicted as groups of particles inside containers of fixed shape and dimension.

Physics
1 answer:
liberstina [14]2 years ago
4 0

Answer:

The answer would be B

Explanation:

Hope you have a good day

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How does mechanical energy relate to the work an object can do
kifflom [539]
I am 11 year old and u just needed to login in so I can't answer ur questions
6 0
3 years ago
Imagine holding a basketball in both hands, throwing it straight up as high as you can, and then catching it when it falls. At w
Alisiya [41]

Answer:

C. At the instant the ball reaches its highest point.

Explanation:

When a body is thrown up, it tends to come down due to the influence of gravitational force acting on the body. The body will be momentarily at rest at its maximum point before falling. At this maximum point, the velocity of the body is zero and since force acting on a body is product of the mass and its acceleration, the force acting on the body at that point will be "zero"

Remember, F = ma = m(v/t)

Since v = 0 at maximum height

F = m(0/t)

F = 0N

This shows that the force acting on the body is zero at the maximum height.

4 0
2 years ago
A 50n box is lifted 2 meters in 3 seconds.
anygoal [31]

F=G=50 N

L=F*d=50*2=100 J

is the work

P=L/t=100/3=33.33 W

4 0
3 years ago
What is the relationship between speed and kinetic energy?
kobusy [5.1K]

Answer:

Kinetic energy depends on the velocity of the object squared. This means that when the velocity of an object doubles, its kinetic energy quadruples.

7 0
1 year ago
Read 2 more answers
A 0.750 kg block is attached to a spring with spring constant 13.0 N/m . While the block is sitting at rest, a student hits it w
trapecia [35]

To solve this problem we will apply the concepts related to energy conservation. From this conservation we will find the magnitude of the amplitude. Later for the second part, we will need to find the period, from which it will be possible to obtain the speed of the body.

A) Conservation of Energy,

KE = PE

\frac{1}{2} mv ^2 = \frac{1}{2} k A^2

Here,

m = Mass

v = Velocity

k = Spring constant

A = Amplitude

Rearranging to find the Amplitude we have,

A = \sqrt{\frac{mv^2}{k}}

Replacing,

A = \sqrt{\frac{(0.750)(31*10^{-2})^2}{13}}

A = 0.0744m

(B) For this part we will begin by applying the concept of Period, this in order to find the speed defined in the mass-spring systems.

The Period is defined as

T = 2\pi \sqrt{\frac{m}{k}}

Replacing,

T = 2\pi \sqrt{\frac{0.750}{13}}

T= 1.509s

Now the velocity is described as,

v = \frac{2\pi}{T} * \sqrt{A^2-x^2}

v = \frac{2\pi}{T} * \sqrt{A^2-0.75A^2}

We have all the values, then replacing,

v = \frac{2\pi}{1.509}\sqrt{(0.0744)^2-(0.750(0.0744))^2}

v = 0.2049m/s

7 0
2 years ago
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