Answer:
The empirical formula of the hydrocarbon is CH.
Explanation:
The following data were obtained from the question:
Mass of hydrocarbon = 2.9 mg
Mass of CO2 = 9.803 mg
Mass of H2O = 2.006 mg
Next, we shall determine the mass of carbon (C) and hydrogen (H) in the compound since hydrocarbon contains carbon and hydrogen only.
This is illustrated below:
Molar mass of CO2 = 12 + (16x2) = 12 + 32 = 44 g/mol
Mass of CO2 = 9.803 mg
Mass of C in the compound =?
Mass of C in the compound =
12/44 x 9.803
= 2.674 mg
Molar mass of H2O = (2x1) + 16 = 2 + 16 = 18 g/mol
Mass of H2O = 2.006 mg
Mass of H in the compound =
2/18 x 2.006
= 0.223 mg
Finally, we shall determine the empirical formula of the hydrocarbon as follow:
Carbon (C) = 2.674 mg
Hydrogen (H) = 0.223 mg
Divide by their molar mass
C = 2.674 /12 = 0.223
H = 0.223 / 1 = 0.223
Divide both side by the the smallest
C = 0.223/0.223 = 1
H = 0.223/0.223 = 1
Therefore, the empirical formula of the hydrocarbon is CH.
Because potassium is a gas that can evolve
The question is incomplete, the complete question is;
Chlorine monoxide accumulates in the stratosphere above Antarctica each winter 3nd plays a key role the formation of the ozone hole above the South Pole each spring Eventually. CIO decomposes acco to the equation: 2CIO(g) rightarrow CL2(g) + O2(g) The second-order rate constant for the decomposition of CIO is 6950000000 M-1 s-1 at a particular temperature Determine the half-life of CIO when its initial concentration is .0000000185 M
Answer:
7.8 * 10^-3 s
Explanation:
Given that the half life of a second order reaction is obtained from the formula;
t1/2 = k-1[A]o-1
t1/2 = 1/k[A]o
second order rate constant (k) = 6950000000 M-1 s-1
initial concentration ([A]o) =0.0000000185 M
t1/2 = 1/6950000000 * 0.0000000185
t1/2 = 7.8 * 10^-3 s
Explanation:
An acid is a substance that ionizes to produce excess hydrogen ion in solutions.
- A concentrated acid contains a high amount of hydrogen ions in solution compared to other ions.
- Such solutions usually ionizes completely.
- A dilute solution contains a high proportion of water and with low amount of hydrogen ions.
- They do not ionize easily and as fast as strong acids.
Answer:
There are many examples of chemical equilibrium all around you. One example is a bottle of fizzy cooldrink. In the bottle there is carbon dioxide (CO2) dissolved in the liquid. There is also CO2 gas in the space between the liquid and the cap.
