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3 years ago

What is electric power?

1 answer:

5 0

Electric power, energy generated through the conversion of other forms of energy, such as mechanical, thermal, or chemical energy.

hope this helps:)sorry if it doesnt

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An apparatus like the one Cavendish used to ﬁnd G has large lead balls that are 5.2 kg in mass and small ones that are 0.046 kg.

Ber [7]

Answer:

The magnitude of gravitational force between two masses is $4.91\times 10^{-9}\ N$ .

Explanation:

Given that,

Mass of first lead ball, $m_1=5.2\ kg$

Mass of the other lead ball, $m_2=0.046\ kg$

The center of a large ball is separated by 0.057 m from the center of a small ball, r = 0.057 m

We need to find the magnitude of the gravitational force between the masses. It is given by the formula of the gravitational force. It is given by :

$F=G\dfrac{m_1m_2}{r^2}\\\\F=6.67259\times 10^{-11}\times \dfrac{5.2\times 0.046}{(0.057)^2}\\\\F=4.91\times 10^{-9}\ N$

So, the magnitude of gravitational force between two masses is $4.91\times 10^{-9}\ N$ . Hence, this is the required solution.

5 0

2 years ago

In longitude waves, the medium moves parallel to the direction of energy transport

adelina 88 [10]

Yep that's correct
And transverse waves move perpendicular to the direction of energy transport

7 0

3 years ago

A rocket in deep space has an empty mass of 150 kg and exhausts the hot gases of burned fuel at 2500 m/s. It is loaded with 600

3241004551 [841]

Answer:

$v(10\,s) \approx 775.387\,\frac{m}{s}$

$v(20\,s)\approx 1905.350\,\frac{m}{s}$

$v(30\,s) \approx 4023.595\,\frac{m}{s}$

Explanation:

The speed of the rocket is given the Tsiolkovsky's differential equation, whose solution is:

$v (t) = v_{o} - v_{ex}\cdot \ln \frac{m}{m_{o}}$

Where:

$v_{o}$ - Initial speed of the rocket, in m/s.

$v_{ex}$ - Exhaust gas speed, in m/s.

$m_{o}$ - Initial total mass of the rocket, in kg.

$m$ - Current total mass of the rocket, in kg.

Let assume that fuel is burned linearly. So that,

$m(t) = m_{o} + r\cdot t$

The initial total mass of the rocket is:

$m_{o} = 750\,kg$

The fuel consumption rate is:

$r = -\frac{600\,kg}{30\,s}$

$r = -20\,\frac{kg}{s}$

The function for the current total mass of the rocket is:

$m(t) = 750\,kg - (20\,\frac{kg}{s} )\cdot t$

The speed function of the rocket is:

$v(t) = - 2500\,\frac{m}{s}\cdot \ln \frac{750\,kg -(20\,\frac{kg}{s} )\cdot t}{750\,kg}$

The speed of the rocket at given instants are:

$v(10\,s) \approx 775.387\,\frac{m}{s}$

$v(20\,s)\approx 1905.350\,\frac{m}{s}$

$v(30\,s) \approx 4023.595\,\frac{m}{s}$

7 0

2 years ago

List examples of two energy transformations- one produced by an electric and the other by a mobile phone.

Phantasy [73]

Answer:

an electric or landline turns electricity into mechanical energy while a mobile phone turns electricity to chemical to heat

Explanation:

3 0

3 years ago

How many neutral points due to a bar magent?

garri49 [273]

Answer:

Two

Explanation:

A neutral point is a point in the magnetic field of a bar magnet where the resultant magnetic field intensity is zero

The neutral point is formed in the region of the combined magnetic field where the magnetic field from the bar magnet is balanced by the horizontal component from the Earth's magnetic field

Two neutral points are formed adjacent to the north and south poles of a bar magnet when the south pole of the bar magnet points in the magnetic north pole of the Earth with the north pole of the bar magnet pointing towards the south pole of the Earth's magnetic field

Two neutral points are also formed on the west and eastern facing sides of a bar magnet when the north pole of the magnet is pointing to the magnetic north of the Earth's magnetic field and the south pole of the bar magnet points south

Therefore, two neutral points are formed for each orientation of the bar magnet when placed horizontally in the Earths magnetic field with the poles of the magnet facing the North and South poles direction of the Earth's magnetic field.

7 0

2 years ago