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LenKa [72]
2 years ago
8

What is the critical angle θcrit for light propagating from a material with index of refraction of 1.50 to a material with inde

x of refraction of 1.00?
Physics
1 answer:
shutvik [7]2 years ago
8 0

Answer:

The critical angle for light is 41.81 degrees.

Explanation:

We have, light is propagating from a material with index of refraction of 1.50 to a material with index of refraction of 1. It is required to find the critical angle for light. It is angle for which the angle of refraction is equal to 90 degrees. It is given by :

\sin\theta_c=\dfrac{n_2}{n_1}\\\\\theta_c=\sin^{-1}(\dfrac{n_2}{n_1})\\\\\theta_c=\sin^{-1}(\dfrac{1}{1.5})\\\\\theta_c=41.81^{\circ}

So, the critical angle for light is 41.81 degrees.

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In the Hydrogen atom, the energy spacing between the is 4.07 x 101 J (Joules). When an is the frequency of the photons emitted?
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Answer:

The frequency of the photon is 3.069\times10^{14}\ Hz.

Explanation:

Given that,

Energy E=4.07\times10^{-19}\ J

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Using relation of energy

E_{4}-E_{2}=\Delta E

Where, \Delta E =  energy spacing

4h\nu-2h\nu=4.07\times10^{-19}

\nu=\dfrac{4.07\times10^{-19}}{2h}

Put the value of h into the formula

\nu=\dfrac{4.07\times10^{-19}}{2\times6.63\times10^{-34}}

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10) The coil of transformer is coated by enamel why​
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What distance does light travel in water, glass, and diamond during the time that it travels 1.0 m in vacuum? The refractive ind
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Answer:

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The time for travel is kept constant for all mediums.

refractive index (n) = \frac{\frac{distance in vacuum}{time} }{\frac{distance in medium}{time} }\\ \\=\frac{distance in vacuum}{distance in medium}

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