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docker41 [41]
3 years ago
15

In each case, you should demonstrate how you worked out your answer, as well as giving the answer.

Physics
2 answers:
Ivanshal [37]3 years ago
7 0

Answer:

First frequency f = 153.846 Hz

Second period T = 1.625 ms

Step by stepplanation:

T = 6.5ms= 6.5*(10^-3)

But T = 1/f

f = 1/T

f = 1(6.5*(10^-3))

f = 153.846 Hz

Now the frequency f is increased by a factor of 3

= 3*153.846

= 461.538

New frequency = 461.538+153.846

= 615.384 Hz

New period T = 1/615.384

Period T = 1.625*10^-3

T= 1.625 ms

irga5000 [103]3 years ago
3 0

Answer:

Explanation:

(a)

Time period, T1 = 6.5 ms

= 6.5 × 10^-3 s

Frequency is the reciprocal of time period.

f1 = 1 / T1 = 1 / (6.5 × 10^-3) = 153.85 Hz

Now the frequency becomes 3 times

f2 = 3 × f1 = 3 × 153.85 = 461.55 Hz

The new period is

T2 = 1 / f2 = 1 / 461.55

= 0.0022 second = 2.22 ms

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Alexus [3.1K]

Given:-

  • Mass of the cart (m) = 35 kg
  • Speed (consider Velocity) = 1.2 m/s

To Find: Momentum of the cart.

We know,

p = mv

where,

  • p = Momentum,
  • m = Mass &
  • v = Velocity.

Thus,

p = (35 kg)(1.2 m/s)

→ p = 42 kg m/s (Ans.)

Conclusion:-

A. ☑️ 42 kilogram - metre per second.

6 0
2 years ago
The density of aluminum is 2.7 g/cm3. A metal sample has a mass of 52.0 grams and a volume of 17.1 cubic centimeters. Could the
Fudgin [204]
 Answer:  
__________________________________________________
            No;  the sample could not be aluminum;
since the density of aluminum, " 2.7 g/cm³ " , is NOT close enough to the density of the sample, " 3.04 g/cm³ " .
________________________________________________
Explanation:
________________________________________________
Density is expressed as "mass per unit volume" ;

  in which:
     "mass, "m", is expressed in units of "g" (grams);  and:
     "Volume, "V", is expressed in units of "cm³ " (such as in this problem); or                                                   in units of "mL" ;
__________________________________________________
            {Note the exact conversion:  " 1 cm³ = 1 mL " .}. 
__________________________________________________
  The formula for density:  D = m/V ;

Given:  The density of aluminum is:  2.7 g/cm³.

Given:  A sample has a mass of 52.0 g ; and Volume of 17.1 cm³ ; could it be aluminum?
_________________________________________________________
Let us divide the mass of the sample by the volume of the sample;
by using the formula:
___________________________________________
            D = m / V ;  

     and see if the value is at, or very close to "2.7 g/cm³ ".  

If it is, then it could be aluminum.
____________________________________________________
The density for the sample:

  D = (52.0 / 17.1)   g/cm³ = 3.0409356725146199 g/cm³ ;
                                              →round to "3 significant figures" ;
                                          = 3.04 g/cm³ .
_______________________________________________
No; the sample could not be aluminum; since the density of aluminum, 
   "2.7 g/cm³ "   is NOT close enough to the density of the sample,
                        "3.04 g/cm³ " .
____________________________________________________
5 0
3 years ago
a sprinter with a mass of 80kg accelerates uniformly from 0 m/s to 9 m/s in 3 s. a.)what is the runners acceleration? b.) what i
Katyanochek1 [597]
Part A: 
Acceleration can be calculated by dividing the difference of the initial and final velocities by the given time. That is,
             a = (Vf - Vi) / t
where a is acceleration,
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Vi is initial velocity, and
t is time

Substituting,
            a = (9 m/s - 0 m/s) / 3 s = 3 m/s²
<em>ANSWER: 3 m/s²</em>

Part B: 
From Newton's second law of motion, the net force is equal to the product of the mass and acceleration,
               F = m x a
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m is mass, and 
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Substituting,
              F = (80 kg) x (3 m/s²) = 240 kg m/s² = 240 N

<em>ANSWER: 240 N </em>

Part C: 
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         d = V₀t + 0.5at²

Substituting,
            d = (0 m/s)(3 s) + 0.5(3 m/s²)(3 s)²
             d = 13.5 m

<em>ANSWER: d = 13.5 m</em>

3 0
2 years ago
A jewellery melts 500g of Silver to pour into a mould. Calculate how much energy was released as the silver solidified.
irga5000 [103]

When silver is poured into the mould the it will solidify

In this process the phase of the Silver block will change from liquid to solid.

This phase change will lead to release in heat and this heat is known as latent heat of fusion.

The formula to find the latent heat of fusion is given as

Q = mL

here given that

m = mass = 500 g

L = 111 kJ/kg

now we can find the heat released

Q = 0.5 * 111 kJ

Q = 55.5 kJ

So it will release total heat of 55.5 kJ when it will solidify

8 0
3 years ago
Two waves can share the same space and pass through one another. What type of interference occurs when the crests of one wave ov
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Question 25 Answer: Destructive interference occurs.

<span>Question 26Answer: The waves are closer together (as they move) because the object is moving toward you.</span>

<span />

4 0
3 years ago
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