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NemiM [27]
3 years ago
6

Which stage of the cell cycle involves the division of the cytoplasm?

Physics
2 answers:
sergij07 [2.7K]3 years ago
7 0

Answer:

C

Explanation:

I just took the question on edge, you can also remember cytokinesis is the division of the cytoplasm by the c at the beginning think of the word cut.

Dmitry_Shevchenko [17]3 years ago
7 0
OK my friend the best answer to this question will be Cytokineses <span />
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If measuring experimental results, what can you predict about the work output of a 1200 Watt hair dryer?
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Toy car in a science experiment covers 1.6 meters in half a second. If a the car travels at a steady speed, how far will it go i
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The answer is D. 32 m.

The simple equation that connects speed (v), time (t), and distance (d) can be expressed as:
v= \frac{d}{t}         ⇒ d=v*t

It is given:
v =  \frac{1.6m}{0.5s} = \frac{1.6m*2}{0.5s*2}= \frac{3.2m}{1s}  = 3.2 m/s
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3 years ago
KIIS FM broadcasts at 102.7 MHz, what is the wavelength of that radio wave?
marysya [2.9K]

Answer:

2.92 m

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As we know, frequency × Wavelength = Speed of light

so here frequency of 102.7 MHz can be written as 102.7× 10⁶ Hz..

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3 0
3 years ago
Two cars, both of mass m, collide and stick together. Prior to the collision, one car had been traveling north at a speed 2v, wh
mel-nik [20]

Answer:u=\frac{v}{2}\sqrt{5-4sin\phi }

Explanation:

Given

Both cars mass is m

and solving problem in Vertical and horizontal direction

considering + y and +x to be positive and u be the final velocity of system

Conserving Momentum in Vertical direction

m(2v)+m(-vsin\phi )=2m(ucos\theta )

2ucos\theta =v(2-sin\theta )------1

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mvcos\phi =2musin\theta-----2

squaring and adding 1 &2

(2u)^2=(2v-vsin\phi )^2+(vcos\phi )^2

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4u^2=5v^2-4v^2sin\phi

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7 0
3 years ago
A 100 N force is applied to a 50 kg crate resting on a level floor. The coefficient of kinetic friction is 0.15. What is the acc
Nookie1986 [14]

The acceleration of the crate after it begins to move is 0.5 m/s²

We'll begin by calculating the the frictional force

Mass (m) = 50 Kg

Coefficient of kinetic friction (μ) = 0.15

Acceleration due to gravity (g) = 10 m/s²

Normal reaction (N) = mg = 50 × 10 = 500 N

<h3>Frictional force (Fբ) =?</h3>

Fբ = μN

Fբ = 0.15 × 500

<h3>Fբ = 75 N</h3>

  • Next, we shall determine the net force acting on the crate

Frictional force (Fբ) = 75 N

Force (F) = 100 N

<h3>Net force (Fₙ) =?</h3>

Fₙ = F – Fբ

Fₙ = 100 – 75

<h3>Fₙ = 25 N</h3>

  • Finally, we shall determine the acceleration of the crate

Mass (m) = 50 Kg

Net force (Fₙ) = 25 N

<h3>Acceleration (a) =?</h3>

a = Fₙ / m

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<h3>a = 0.5 m/s²</h3>

Therefore, the acceleration of the crate is 0.5 m/s²

Learn more on friction: brainly.com/question/364384

8 0
2 years ago
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