Answer:
Below is the calculation of all the required quantities. From the calculations, Vx must change, the velocity before hitting the ground must change and the angles also must change.
Explanation:
Below is an attachment that contains the calculation steps.
Thank you for reading.
Answer:
Corect answer is D
Explanation:
Assuming that the C
O
2 gas is behaving ideally, therefore, we can use the ideal gas law to find the pressure increase in the container by:
P
V=nRT ⇒ P=n
R
T
/V
n=no of moles of the gas = mass/molar mass
Molar mass o f C
O
2=44g/mol, mass = 44g
mole n = 1mole
T=20C=293K
R=0.0821L.atm/mol.K
P=nRT/V
P = 1 x 0.0821 x 293/2
P = 12atm
Answer:
3.33 seconds
Explanation:
We can use the velocity formula [ v = u + at ] to solve.
Find the value "u".
135km/h -> 135km*1000m/3600s -> 37.5m/s
Find the value "v".
75km/h -> 75km*1000m/3600s -> 20.83m/s
Keep in mind we are dealing with "deceleration" so when we input 5.0m/s into the formula, it will be a negative value.
Now, find "t" which is the value we aren't given with the values we're given in the question.
20.83 = 37.5 - 5t
-16.67 = -5t
3.33 = t
Best of luck!
Answer: 150 m
Explanation:
velocity = 22 m/s
t = 6.8 s
velocity = 
distance = velocity × time
= 22 × 6.8
= 149.6 m
≈ 150 m
option C
