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STatiana [176]
3 years ago
9

What does the statement “Mass is conserved during a chemical reaction” mean?

Chemistry
1 answer:
JulijaS [17]3 years ago
3 0
This is the law of conservation of mass, which means that, for ex., if I burn my book, the mass of the smoke, cinders and ashes I'm left with will be the same as my original book. 

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List four observations that suggest chemical change is occurring
allsm [11]

Answer:

Examples of Chemical Changes

Burning wood.

Souring milk.

Mixing acid and base.

Digesting food.

Cooking an egg.

Heating sugar to form caramel.

Baking a cake.

Rusting of iron.

8 0
2 years ago
How can soap affect the surface tension
mario62 [17]
By breaking the hydrogen bonds that cause surface tension
5 0
3 years ago
The best way seperate salt fron wateris with the use of
ExtremeBDS [4]

You can boil or evaporate the water and the salt will be left behind as a solid. If you want to collect the water, you can use distillation. This works because salt has a much higher boiling point than water. One way to separate salt and water at home is to boil the salt water in a pot with a lid. So, I would say maybe oil.

6 0
2 years ago
Suppose a 0.025M aqueous solution of sulfuric acid (H2SO4) is prepared. Calculate the equilibrium molarity of SO4−2. You'll find
FromTheMoon [43]

<u>Answer:</u> The concentration of SO_4^{2-} at equilibrium is 0.00608 M

<u>Explanation:</u>

As, sulfuric acid is a strong acid. So, its first dissociation will easily be done as the first dissociation constant is higher than the second dissociation constant.

In the second dissociation, the ions will remain in equilibrium.

We are given:

Concentration of sulfuric acid = 0.025 M

Equation for the first dissociation of sulfuric acid:

       H_2SO_4(aq.)\rightarrow H^+(aq.)+HSO_4^-(aq.)

            0.025          0.025       0.025

Equation for the second dissociation of sulfuric acid:

                    HSO_4^-(aq.)\rightarrow H^+(aq.)+SO_4^{2-}(aq.)

<u>Initial:</u>            0.025            0.025      

<u>At eqllm:</u>      0.025-x          0.025+x        x

The expression of second equilibrium constant equation follows:

Ka_2=\frac{[H^+][SO_4^{2-}]}{[HSO_4^-]}

We know that:

Ka_2\text{ for }H_2SO_4=0.01

Putting values in above equation, we get:

0.01=\frac{(0.025+x)\times x}{(0.025-x)}\\\\x=-0.0411,0.00608

Neglecting the negative value of 'x', because concentration cannot be negative.

So, equilibrium concentration of sulfate ion = x = 0.00608 M

Hence, the concentration of SO_4^{2-} at equilibrium is 0.00608 M

4 0
3 years ago
Does anyone know how to do this
marshall27 [118]

Answer:

Explanation:

1-butanol has 4 carbon atoms with an OH group at the first carbon atom.

Dichlorodifluoromethane has 1 carbon atom with 2 chlorine atoms and 2 fluorine atoms.

8 0
3 years ago
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