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swat32
4 years ago
13

A sealed vessel containg helium, chlorine and fluorine has a total pressure of 205 kpa and partial pressures of 15 kpa for chlor

ine and 89 kpa for fluorine. what is the pressure for helium in kpa
Chemistry
1 answer:
MrRa [10]4 years ago
7 0

According to Dalton's law of partial pressure

The total pressure of a mixture of ideal gases is sum of the partial pressures of each gas present in the mixture

So if we know the partial pressure of all the gases we can determine the total pressure of the mxiture by adding all of them.

Thus

Ptotal = PCl2 + PF2 + PHe

Thus

Partial pressure of helium = 205 - ( 89 + 15) = 101 kPa

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If you added 15,000 calories to 2.0 L of water that was at 25.0 degrees C, what temperature would it be at when you finished?
rewona [7]

<u>Answer:</u>

<em>When we finish, the temperature would be 32.5℃</em>

<em></em>

<u>Explanation:</u>

Density of water = mass/volume

So,

Mass of water = Density × Volume

\\\\$=1.0   \times  2.0 L$\\\\$=1.0 \frac{g}{m L} \times 2000 m L$\\\\$\quad=2000 g$

$Q=m \times c \times \Delta T$

where

\Delta T = Final T - Initial T

Q is the heat energy in calories

c is the specific heat capacity (for water 1.0  cal/(g℃))  

m is the mass of water

plugging in the values  

$15000 \mathrm{Cal}=2000 \mathrm{g} \times 1.0 \frac{\mathrm{cal}}{\mathrm{g}^{\circ} \mathrm{C}} \times \Delta T$

\\$\Delta T=\frac{15000 \mathrm{cal}}{2000 \mathrm{g} \times \frac{1.0 \mathrm{cal}}{g^{\circ} \mathrm{C}}}$\\\\$\Delta T=7.5^{\circ} \mathrm{C}$

Final T = ∆T + Initial T

= 7.5℃ + 25℃ = 32.5℃ (Answer).

5 0
3 years ago
What is the molar mass of a gas if 0. 473 g of the gas occupies a volume of 376 ml at 23. 0°c and 1. 90 atm?.
frozen [14]

Answer:

The molecular weight of the unknown gas is 16.1 g/mol.

6 0
2 years ago
An alien civilization has different names and symbols for six elements. Place each element in the correct location in the period
Margarita [4]

Answer:

why whould I know that!!??

Explanation:

3 0
3 years ago
Read 2 more answers
If you react 156.0 g of calcium chloride with an excess NaOH, how much sodium chloride should you get?
laiz [17]

Answer:

164.3g of NaCl

Explanation:

Based on the chemical equation:

CaCl2 + 2NaOH → 2NaCl + Ca(OH)2

<em>where 1 mole of CaCl2 reacts with 2 moles of NaOH</em>

To solve this question we must convert the mass of CaCl2 to moles. Using the chemical equation we can find the moles of NaCl and its mass:

<em>Moles CaCl2 -Molar mass: 110.98g/mol-</em>

156.0g CaCl₂ * (1mol / 110.98g) = 1.4057 moles CaCl2

<em>Moles NaCl:</em>

1.4057 moles CaCl2 * (2mol NaCl / 1mol CaCl2) = 2.811 moles NaCl

<em>Mass NaCl -Molar mass: 58.44g/mol-</em>

2.811 moles NaCl * (58.44g / mol) = 164.3g of NaCl

7 0
3 years ago
A 5.00-cm cube of magnesium has a mass of 217.501 g. What is the density of magnesiummetal?
Doss [256]

Answer:

d = 43.5 g/cm³

Explanation:

Given data:

Mass of magnesium cube = 217.501 g

Volume of magnesium cube = 5.00 cm³

Density of magnesium cube = ?

Solution:

Formula:

d = m/v

d = density

m = mass

v = volume

by putting values,

d = 217.501 g/ 5.00 cm³

d = 43.5 g/cm³

8 0
3 years ago
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