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Shtirlitz [24]
3 years ago
15

Rutherford's alpha particle scattering experiment was responsible for the discovery of​

Chemistry
1 answer:
Bingel [31]3 years ago
7 0

Answer:

Atomic Nucleus

Explanation:

Atomic Nucleus

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Based on the synthesis reaction, what would the product of the reaction be? NaPO3 + CuO → ? NaO + CuPO3 Na + P + Cu + O4 NaCuPO4
trapecia [35]

Answer:

C

Explanation:

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5 0
3 years ago
Read 2 more answers
Equilibrium is established in a reversible reaction when
avanturin [10]
The correct answer among the options given is B. . When the forward and reverse paths of a change occur at the same rate, <span>the system is in equilibrium specifically in dynamic equilibrium.<span> Dynamic equilibrium is the balance in a process that is continuing. </span></span>
6 0
4 years ago
Calculate how many moles of NH3 form when each quantity of reactant completely reacts according to the equation:
Leya [2.2K]
<span>1) Use the balanced chemical equation to find the molar ratios (proportions) of each product and reactant.

3N2H4(l)→4NH3(g)+N2(g)

=> molar ratios: 3 mol N2H4 : 4 mol NH3

2) Use the product to reactant molar ratio, and the quantity of reactant to determine the yield:

2.0 mol N2H4 * [4mol NH3] / [3mol N2H4] = 2*4/3 mol NH3 = 2.7 mol NH3

Answer: 2.7 mol
 
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8 0
3 years ago
2 A(g) + B(g) ---&gt; 2 C(g)Rate = k [A][B]At the beginning of one trial of this reaction, [A] = 3.0 M and [B] = 1.0 M. The obse
Orlov [11]

Answer:

Lmol⁻¹s⁻¹

Explanation:

The rate law of the given reaction is:-

Rate=k[A][B]

Wherem, k is the rate constant.

Given that:-

Rate = 0.36 mol/Lsec = 0.36 M/sec

[A] = 3.0 M

[B] = 1.0 M

Thus,

Applying in the equation as:-

0.36 M/sec =k × 3.0 M× 1.0 M

k = 0.12 (Ms)⁻¹ = 0.12 Lmol⁻¹s⁻¹

<u>The units of k = Lmol⁻¹s⁻¹</u>

6 0
3 years ago
Determine if the electron configurations are valid or invalid
Hunter-Best [27]

Answer:

1) A (valid)

2) B (Invalid)

3) B (Invalid)

4) A (valid)

5) B (Invalid)

6) B (Invalid)

Explanation:

Electronic configuration:

The electronic configuration is the arrangnment of electrons in orbitals (s, p, d, f, g, h so on) according to quantum  number and Aufbau rule.

An atom of element have orbitals, and electrons are revolving in it.

There are quantum numbers that describe the number of electron in specific shell.

The Principle quantum number is denoted by "n" and can not be "0".

These "n" is K, L, M, N and electrons are distribution in it.

K =2

L= 8

M= 18

According to Aufbau electron occupied in the lowest energy level before occupying the highest energy level.

According to this the electronic configuration is

1s², 2s², 2p⁶ and so on....

So,

"s" orbital accommodate maximum of 2 electrons

"p" orbital accommodate maximum of 6 electrons

"d" orbital accommodate maximum of 10 electrons

"f" orbital accommodate maximum of 14 electrons

and the coefficient 1, 2, 3, 4 are energy level of orbitals.

The 1st orbital is 1s and it only can occupy 2 electrons the next coming electron goes into 2s that also can occupy 2 electrons and the further electrons will go to 2p orbital.

So keeping in mind all above details we investigate all option one by one

1.  A (valid)

1s², 2s², 2p⁶, 3s², 3p⁶, 4s², 3d¹⁰, 4p⁵

This is valid option. number of electrons are rightly accommodated in orbitals. Also 3d is higher energy level than 4p.

______________

2.  B (Invalid)

1s², 2s², 2p⁶, 3s², 3p⁷

This is invalid option. number of electrons are not rightly accommodated in orbitals as "p" orbital can only accommodate 6 electrons and not more than 6.

________________

3.  B (Invalid)

[Xe], 7s², 6d¹, 5f⁸

This is Invalid option. Number of electrons are not rightly accommodated in orbitals. There should 5f orbital before 6d.

______________

4.  A (valid)

[Kr] 5s², 4d¹⁰, 5p⁵

This is valid option. number of electrons are rightly accommodated in orbitals.

______________

5.  B (Invalid)

[He]--

This is invalid option. There is no exact explanation of electron distribution in orbitals.

______________

6.  B (Invalid)

1s², 2s², 2p⁶, 3s³, 3p⁶, 4s², 3d¹⁰, 4p⁶, 5s--

This is invalid option. number of electrons are not rightly accommodated in orbitals. As "s" can accommodate only 2 electrons not 3 electrons. also there is no details of 5s

______________

4 0
4 years ago
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