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mr Goodwill [35]
3 years ago
10

What material was added to powdered rock during tuttle and bowen's experiments?

Chemistry
1 answer:
Rzqust [24]3 years ago
4 0

Answer:

water was added to powdered rock

Explanation:

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What reaction is depicted by the given equation: au3 3e− au
mrs_skeptik [129]
This is a reduction half-reaction. Initially, gold exists as Au^{3+}, and after the reaction, it has been converted to elemental gold. To make this possible, three electrons must be added to <span>Au^{3+}. This fits within the definition of reduction reactions, where the reactant gains electrons in the reaction.</span>
3 0
3 years ago
Identify the single displacement reaction. 2H 2 + O 2 ⟶ 2H 2O Al 2S 3 ⟶ 2Al + 3S Cl 2 + 2KBr ⟶ 2KCl + Br 2 C 4H 12 + 7O 2 ⟶ 6H 2
ozzi

Answer: Cl_2+2KBr\rightarrow 2KCl+Br_2

Explanation:

A single displacement reaction is one in which a more reactive element displaces a less reactive element from its salt solution. Thus one element should be different from another element.

Cl_2+2KBr\rightarrow 2KCl+Br_2

Synthesis reaction is defined as the reaction where substances combine in their elemental state to form a single compound.2H_2+O_2\rightarrow 2H_2O

Decomposition reaction is defined as the reaction where a single substance breaks down into two or more simpler substances.

Al_2S_3\rightarrow 2Al+3S

Combustion is a type of chemical reaction in which hydrocarbons burn in the presence of oxygen to form carbon dioxide and water along with heat.

C_4H_{12}+7O_2\rightarrow 6H_2O+4CO_2

6 0
4 years ago
The following information is to be used for the next 2 questions. In order to analyze for Mg and Ca, a 24-hour urine sample was
Ainat [17]

Answer:

Explanation:

From the given information:

The concentration of metal ions are:

[Ca^{2+}]= \dfrac{0.003474 \ M \times 20.49 \ mL}{10.0 \ mL}

[Ca^{2+}]=0.007118 \ M

[Mg^2+] = \dfrac{0.003474 \ M\times (26.23  - 20.49 )mL}{10.0 \ mL}

=0.001994 \ M

Mass of Ca²⁺ in 2.00 L urine sample is:

= 2.00 L \times 0.001994 \dfrac{mol}{L} \times \dfrac{40.08 \ g}{1 \ mol}

= 0.1598 g

Mass of Ca²⁺ = 159.0 mg

Mass of Mg²⁺ in 2.00 L urine sample is:

= 2.00 L \times 0.007118 \dfrac{mol}{L} \times \dfrac{24.31 \ g}{1 \ mol}

= 0.3461 g

Mass of Mg²⁺ = 346.1 mg

5 0
3 years ago
If the pH of vinegar is 3.0, what is the concentration of H+ in vinegar?
Cerrena [4.2K]

Answer: The concentration of H^{+} ions in vinegar is 0.001 M.

Explanation:

Given: pH = 3.0

pH is the negative logarithm of concentration of hydrogen ion.

The expression for pH is as follows.

pH = - log [H^{+}]

Substitute the value into above expression as follows.

pH = - log [H^{+}]\\3.0 = - log [H^{+}]\\conc. of H^{+} = antilog (- 3.0)\\= 0.001 M

Thus, we can conclude that the concentration of H^{+} ions in vinegar is 0.001 M.

5 0
3 years ago
Which of the following statements about protons are true?
attashe74 [19]
The second on it true
4 0
3 years ago
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