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victus00 [196]
3 years ago
7

Describe how air pressure is exerted on objects.

Physics
1 answer:
Delicious77 [7]3 years ago
5 0
<span>The same amount of pressure is exerted on all sides of the object equally. If you had 13 psi, then that means on the top of the object, 13 psi would be pushing in on the object. From the bottom, 13 psi would be pushing up on the object. Same goes for all the sides as well. The pressure pushes 'in' on the object.</span>
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An object travels at constant velocity of 3 m/s for a time period of 7.15 s. What is its displacement over this time?
son4ous [18]

Hi there!

We can use the following equation for constant velocity:

\large\boxed{d = vt}

d = displacement (m)

v = velocity (m/s)

t = time (s)

Plug in the givens:

d = 3 * 7.15 = \boxed{21.45 m}

5 0
3 years ago
Define alpha and beta​
elena55 [62]

alpha is the excess return on an investment after adjusting for market related volatility and random fluctuations.

beta is a measure of volatility relative to a benchmark ,such as the S&P 500.

Explanation:

alpha and beta are two different parts of an equation used to explain the performance of stocks and investments funds. But in maths alpha and beta is the Greek alphabet

4 0
3 years ago
Robert bought 20 games for his grandkids. If he spent a total of $199.80, how much did each game cost if
RideAnS [48]

Answer:

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Explanation:

4 0
4 years ago
A motorist drives north for 35.0 minutes at 85.0 kph. He then stops for 15.0 minutes. The motorist then drives 130.0 km in 2.0 h
o-na [289]

Answer:

A. 216.36 \frac{km}{h}

B. 96.56 \frac{km}{h}

Explanation:

Let s_{1} be the distance in first part.

s_{1} = velocity × time

s_{1} = 85 × \frac{35}{60}

s_{1} = 49.58 km

Let s_{2} be the distance in first part.

s_{2} = 130 km

Average velocity = \frac{Total displacement}{Total time}

When second leg of the trip is

A. Toward north

Average velocity = \frac{[tex] s_{1} + s_{2}}{Total time}  [/tex]

Average velocity = \frac{130+49.58}{0.25+0.58}

Average velocity =216.36 \frac{km}{h}

B. Toward south

Average velocity = \frac{[tex] s_{1} - s_{2}}{Total time}  [/tex]

Average velocity = \frac{130-49.58}{0.25+0.58}

Average velocity =96.56 \frac{km}{h}


3 0
3 years ago
What is the magnitude of speed of a person goes 75 meters east followed by 20 meters west in 4 seconds
marshall27 [118]

Answer:23.75 m/sec

Explanation:

Total distance is 75+20=95m

Speed is =95/4

23.75 m/s

4 0
3 years ago
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