Answer:
255 5,6 7,78
Step-by-step explanation:
Answer:
12 pull
As 48 seconds + 20 seconds push = 68 seconds
Step-by-step explanation:
Because she did 10 push = 20 seconds = 2 seconds each
12 pull = 48 seconds = 4 seconds each
= 68 seconds combined.
Workings;
18 seconds found for the first set
We then find a divider of 68 and know that
6 x 3 = 18 seconds push
12 x 3 =36 seconds pull T= 54
14 left over = 1 x 12 seconds pull
+ 2 seconds push
= 10 push = 20 seconds combined.
= 12 pull = 48 seconds combined.
Answer:
A???
Step-by-step explanation:
i don't understand the question
but i feel like the question you just asked is 1-2 =
i hope this helped
(i doubt it did)
We know that the law of sines states that:

For simplicity, let:

In triangle A1BC this leads to:

Therefore:

Now, triangle A2BC is isosceles which means that both the base angles are equal, since angle CA1B and A2A1B are supplementary we have: