Answer:
69×10⁻³ m
Explanation:
The linear thermal expansion coefficient for water is α = 69×10⁻⁶ K⁻¹.
Thermal expansion equation:
α ΔT = ΔL / L
Given ΔT = 1.00ºC = 1.00 K and L = 1.00 km = 1.00×10³ m:
(69×10⁻⁶ K⁻¹) (1.00 K) = ΔL / (1.00×10³ m)
ΔL = 0.069 m
ΔL = 69×10⁻³ m
Answer:
The initial arrow's velocity is 40,9 m/s at 11.9° from the horizontal
Explanation:
<em>In order to find the inital velocity we need to determine its components and the angle that the arrow is launched at.</em>
<em>For horizontal component, we will have:</em>
<em>ν cos(θ)t = x ⇒ cos(θ) = x/νt</em>
<em>For vertical component we will have:</em>
<em>h= v sin(θ)t ₋ gt²÷ 2 ⇒ sin (θ) = h + gt²÷2/νt</em>
<em>From the two equations we got, after noting that the vertical displacement is 3m, we can calculate </em>
<em>tan(θ) = h +gt²÷2/νt/ x÷νt = h+ gt²÷2/x = 3+ 9.8.0.5²÷2/20 = 0.21125</em>
<em>Now we can calculate θ = tan⁻¹(0.21125) ≈ 11.9°</em>
<em>Now that we know the angle we can subtitute at any of the expressions for the two components of the velocity . Let's do this subsitution at the horizontal component:</em>
<em>ν cos(θ)t= x =ν = x/tcos(θ)= 20/ 0.5cos(11.9) ≈ 40.9 m/s.</em>
<em></em>
Answer:
Explanation:
It is given that the sphere is insulated from ground and a large charge is placed on the sphere. The charge on the hollow sphere will always remain on the outer surface of the sphere and there will be no charge on the inner surface of the sphere.
If a person touches the inner surface of the sphere then he will not be harmed as there is no charge on the inner surface of the sphere.
If a person carries the charge of the opposite sign of the same magnitude then the sphere and person get neutralized upon touching the sphere.
If a person does not touches the sphere then the charge on the outer surface will be zero and there will be a positive charge on the inner surface of the sphere
I am walking to the end of the room holding three textbooks.
Playing tug of war
Moving boxes to move out of your house
