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enot [183]
3 years ago
14

A cliff jumper runs off a 15 m high cliff. Rocks extend 3.0 m past the cliff bottom. We can ignore air resistance.What is the mi

nimum horizontal velocity needed to clear the rocks?
Physics
1 answer:
posledela3 years ago
6 0
The correct answer would be 1.7 m/s:

Start with what you know. In the y-direction, we know the jumper must fall 15 meters and starts with 0 velocity in the y direction. You can also assume that the acceleration of gravity is pulling down on the jumper at 9.8 m/s. Once you have these three you can plug it into kinematic a equation to find time

x=Vot+1/2at^2
15=(0)t+1/2(9.8)(t)^2
t=1.75

You get time=1.75 seconds. Since this is a kinematics problem, both the x and y direction have the same amount of time. You can then see that the x displacement is 3 to avoid the rocks, and acceleration is 0 in the x direction because no force is speeding it up. Therefore you can use the same equation to find initial velocity and final velocity, which are gonna be the same because we have 0 acceleration:

X=Vot+1/2at^2
3=Vi(1.75)+1/2(0)(1.75)^
Vi=1.7

1.7 is your answer

I have my work in the picture I really like to make charts to help keep everything organized if that helps you
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The linear impulse delivered by the hit of a boxer is 202 N · s during the 0.244 s of contact. What is the magnitude of the aver
zlopas [31]

Answer: Magnitude of the average force exerted on the glove by the other boxer is 827.86 N (approximately 828 N).

Explanation: Impulse is defined as the force acting on an object for a short period or interval of time.

Mathematically it is given by the relation:

Impulse = Force \times Time

According to the numerical values given in the question, I = 202 Ns and T = 0.244 s

So, Force F = \frac{Impulse}{Time} = \frac{202}{0.244} = 827.86 N

Magnitude of the average force exerted on the glove by the other boxer is 827.86 N (approximately 828 N).

7 0
3 years ago
Question #14
Katena32 [7]

The decrease in energy in the hydrogen molecule is what allows its formation on Earth, but in stars the great energy of the explosion has a kinetic energy so great that electrons cannot bind to another atom, which is why hydrogen has a single atom.

The hydrogen molecule is a form that two hydrogen atoms share their electrons decreasing the total energy of the molecule, this bond has a covalent and hydrogen bonding characteristic.

In a stellar explosion, the energy released increases the energy of the hydrogen atom, for which we have two possibilities:

  • Its electron is lost, so we are in a single proton, in the case of structures where the proton and the elector are
  • The hydrogen atom remains but the energy of the atom is very high so the kinetic energy of the electron prevents the electron from being shared by the other atom and the molecule cannot be formed.

When the atoms are thrown into space, the separation between them is so high that it does not allow electrons to be shared and molecules cannot be formed either.

In conclusion, the decrease in energy in the hydrogen molecule is what allows its formation on Earth, but in stars the great energy of the explosion has a kinetic energy so great that electrons cannot join another atom, which is why the hydrogen has only one atom.

Learn more about the Hydrogen atom here:

brainly.com/question/22464200

6 0
2 years ago
Not sure what to put this under
cestrela7 [59]

family 16 cause i said so XD


5 0
3 years ago
Three identical train cars, coupled together, are rolling east at 1.8 m/s . A fourth car traveling east at 4.5 m/s catches up wi
Vedmedyk [2.9K]

Answer:

v = 1.98\ m/s

Explanation:

consider the mass of each train car be m

m₁ = m₂ = m₃ = m

speed of the three identical train

u₁ = u₂ = u₃ = 1.8 m/s

m₄ = m             u₄ = 4.5 m/s

m₅ = m              u₅ = 0 (initial velocity )

final velocity

v₁ = v₂ = v₃ = v₄ = v₅ = v

using conservation of momentum

m₁u₁ + m₂u₂ + m₃u₃ + m₄u₄ + m₅u₅ = m₁v₁ + m₂v₂ + m₃v₃ + m₄v₄ + m₅v₅

m (1.8 + 1.8 + 1.8 +4.5) = 5 m v

v = \dfrac{9.9}{5}

v = 1.98\ m/s

5 0
3 years ago
Explain why the extrapolated temperature is used to determine the maximun temperature of the mixture rather than the highest rec
Oksi-84 [34.3K]
The extrapolated temperature is used to define the maximum temperature of the mixture relatively than the highest recorded temperature in which the conclusion will effect in a higher specific heat value. Heat is bound to escape from whatever apparatus is using, therefore it is needed to account for the loss of the heat that does not go into increasing the temperature of the mixture. 
6 0
3 years ago
Read 2 more answers
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