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svp [43]
3 years ago
15

A hockey puck slides across the ice at a constant velocity. Is the sliding puck in equilibrium? Why or why not?

Physics
1 answer:
geniusboy [140]3 years ago
3 0

Answer:

Since the hockey puck is moving at constant velocity

So here we will have

F_{net} = ma

where we have

a = acceleration of the object

m = mass of object

so here since we know that acceleration is defined as rate of change in velocity

so here we will say that

a = \frac{dv}{dt}

a = 0

so we have

F_{net} = 0

so we will say that hockey puck is in equilibrium as there is no net force of it

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A particle with charge 7.76×10^(−8)C is moving in a region where there is a uniform 0.700 T magnetic field in the +x-direction.
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Answer:

The  z-component of the force is  \= F_z  =  0.00141 \ N    

Explanation:

From the question we are told that

          The charge on the particle is q =  7.76 *0^{-8} \  C    

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           The  velocity of the particle toward the y-direction is

v_y  =  -2.61*10^{4}\ \r j  \ m/s

           The  velocity of the particle toward the z-direction is

v_y  =  -5.85*10^{4}\ \r k  \ m/s

Generally the force on this particle is mathematically represented as

          \= F  =  q (\= v   X  \= B )

So  we have    

          \= F  =  q ( v_x \r  i + v_y \r  j  +  v_z \r k  )  \ \ X \ (  \= B i)

         \= F  = q (v_y B(-\r  k) + v_z B\r j)      

  substituting values

       \= F  = (7.7 *10^{-8})([ (-2.61*10^{4}) (0.700)](-\r  z) + [(5.58*10^{4}) (0.700)]\r y)    

      \= F=  0.00303\ \r j +0.00141\ \r k                  

So the z-component of the force is  \= F_z  =  0.00141 \ N    

Note :  The  cross-multiplication template of unit vectors is  shown on the first uploaded image  ( From Wikibooks ).

7 0
3 years ago
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Answer:

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