Answer:
1.045 m from 120 kg
Explanation:
m1 = 120 kg
m2 = 420 kg
m = 51 kg
d = 3 m
Let m is placed at a distance y from 120 kg so that the net force on 51 kg is zero.
By use of the gravitational force
Force on m due to m1 is equal to the force on m due to m2.



3 - y = 1.87 y
3 = 2.87 y
y = 1.045 m
Thus, the net force on 51 kg is zero if it is placed at a distance of 1.045 m from 120 kg.
Answer:
0.0979 N/c
Explanation:
Electric field, E is given as a product of resistivity and current density
E=jP where P is resistivity and j is current density
But the current density is given as
where I is current and A is area and 
Substituting this into the first equation then 
Given diameter of 0.259 cm= 0.00259 m and the radius will be half of it which is 0.001295 m

Answer:
150J
Explanation:
Formula : <u>Work</u><u> </u><u>done</u>
Force x distance
work done = force x distance
Distance should be measured in meters
300÷100=3m
work done = 450 x 3
=150J
Answer:
The displacement of the volleyball is 2.62 m
Explanation:
Given;
initial velocity of the volleyball, u = 7.5 m/s
final velocity of the volleyball, v = 2.2 m/s
displacement of the volleyball, d = ?
Apply the following kinematic equation;
v² = u² - 2gd
2gd = u² - v²

Therefore, the displacement of the volleyball is 2.62 m
Answer:
5 m/s2, left
Explanation:
We can solve the problem by applying Newton's second law of motion, which states that:

where:
is the net force acting on an object
m is the mass of the object
a is its acceleration
In this problem, we have:
(to the left) is the net force on the object
m = 2.0 kg is the mass
So, the acceleration is:
in the same direction as the force (left).